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Ilya [14]
3 years ago
7

Why are you able to find a greatest common factor but not a greatest common multiple

Mathematics
1 answer:
Ugo [173]3 years ago
7 0
Because you can always multiply a number infinitely, but there is a finite number of whole number factors.
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A rate of deposit of dust from unpolluted air is 10.0 tons per square mile per month (30 days). what is this dust fall, in milli
valina [46]
The rate of dust deposition is
Rate= \frac{10 \,tons}{mi^{2}-30\,days} = \frac{1}{3} \, \frac{tons}{mi^{2}-day}

Note that
1 ton = 9.07185 x 10⁵ g = 9.07185 x 10⁸ mg
1 mi = 1609.34 m = 1.60934 x 10³ m
1 day = 24 h

Therefore
Rate=( \frac{1}{3}\, \frac{tons}{mi^{2}-day} )*( \frac{1}{24} \, \frac{day}{h} )*( \frac{1}{1.60934\times10^{3}}\, \frac{mi}{m} )^{2}*(9.07185\times10^{8}\, \frac{mg}{ton})\\= 4.865\, \frac{mg}{m^{2}-h}

Answer: 4.865\, \frac{mg}{m^{2}-h}

3 0
3 years ago
A recipe that makes 24 cupcakes calls for 5 1/2 cups of flour. How much flour is needed to make 30 cupcakes?
Reptile [31]

Answer: D hope this helps

5 0
3 years ago
What is the difference of the polynomials:
Galina-37 [17]

Answer:

(6+4x+8)-4-2x-5

6-4+4x-2x+8-5

2+2x+3.

5 0
3 years ago
If y = 3x +1 were changed to y = x+1, how would the graph of the new function
nikitadnepr [17]

Answer:

Step-by-step explanation:

The standard form of a linear equation, a line, is y = mx + b, where m is the slope. The rule is the higher this value of m, the steeper the graph is. If we have the original equation y = 3x + 1, its slope m is 3; in the "new" equation, y = x + 1, its slope is 1. So the "new" equation would be less steep because the slope is a lower value than the original.

7 0
3 years ago
13-28 Sketch the region enclosed by the given curves and find its area.
Gala2k [10]

Answer:

Area (A)  0.0682

Step-by-step explanation:

The sketch for the region enclosed by the given curves can be found in the image attached below.

From the image below;

The two curves intersect in the area of tan 9x = 2 sin 9x

Recall that:

making x the subject; then:

The subdivision of the domain is in two intervals

where;

Area (A) =

Area (A) = 0.06818

Area (A)  0.0682

4 0
3 years ago
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