Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
X⁴ - 81 = x⁴ - 9² (Difference of 2 squares, then we an write it:
(x²-3)(x²+3) =0, → then (x²-3) = 0 and (x²+3)=0
(x²-3) = 0 → x² = 3 → x = +√3 and x = -√3
(x²+3) =0 → x² = -3 → x = +√-3 and x = -√3→ or i√3 AND x = -i√3
A{ -3 , +3 , -i√3 , i√3}
Multiply by two
2/5 x 2/1 = 4/5
Answer: 19,11,17 and 13,22,14
Step-by-step explanation:
The two smallest numbers (11, 17) added together must be a bigger number than the biggest number (19)...... 11 + 17 = 28
28> 19 :)
