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3 years ago

Use the image to the right for this question:

Mathematics

1 answer:

masya89 [10]3 years ago

7 0

Answer:

x=4

Step-by-step explanation:

Use SohCahToa

sin 45 = 7/h

h = 7sin45

use the calculater

h = 4.949747468 = 5

do it again for the next triangle

sin 55 = 5/x

x = 5sin55

use the calculater

x = 4.095760221 = 4

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the equation is -2x² = 4-3 (x + 1) and the question is justify that it is a 2nd degree equation with the unknown x complete.

Serggg [28]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

-2x² = 4-3 (x + 1)

-2x² = 4-3x-3

-2x² = -3x -7

0 = 2x² -3x -7

We know that the degree of the equation is the highest power of x variable in the given equation.

In the equation 0 = 2x² -3x -7 the highest power of x variable in the given equation is 2.

Thus, the degree of the equation is 2.

Also in the equation 0 = 2x² -3x -7, the unknown variable is 'x'.

Let us determine the value 'x'

2x² -3x -7 = 0

Add 7 to both sides

$2x^2-3x-7+7=0+7$

$2x^2-3x=7$

Divide both sides by 2

$\frac{2x^2-3x}{2}=\frac{7}{2}$

$x^2-\frac{3x}{2}=\frac{7}{2}$

Add (-3/4)² to both sides

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{7}{2}+\left(-\frac{3}{4}\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{65}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{65}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{3}{4}=\sqrt{\frac{65}{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{\sqrt{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{4}$

Add 3/4 to both sides

$x-\frac{3}{4}+\frac{3}{4}=\frac{\sqrt{65}}{4}+\frac{3}{4}$

$x=\frac{\sqrt{65}+3}{4}$

similarly solving

$x-\frac{3}{4}=-\sqrt{\frac{65}{16}}$

$x=\frac{-\sqrt{65}+3}{4}$

So the solution of the equation will have the values of x such as:

$x=\frac{\sqrt{65}+3}{4},\:x=\frac{-\sqrt{65}+3}{4}$

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3 years ago

Fourteen less than a number is 45. Find the number

Elina [12.6K]

59 is the answer all you do is add 14 to 45 and you'll get t9

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3 years ago

What is the volume of a right cylinder which has a base radius of 14 inches and a height of 2 inches?

Burka [1]

Answer:

B) 1,231 in3

Step-by-step explanation:

V = pi * r^2 * h

V = 3.14 * (14 in.)^2 * 2 in.

V = 1230.88 in.^3

Answer: B) 1,231 in3

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3 years ago

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I really need help on this question offering 10 points if anybody could help me with this with proof I'd be very thankful

kozerog [31]

Answer:

n=15

Step-by-step explanation:

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3 years ago

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olchik [2.2K]

-(-9)=9 is true because a negative to a negative is positive

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3 years ago