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3 years ago

7

Using the remainder theorem, which is not a factor of

xFormula1" title="x^4-3x^3-17x^2+39x-20?" alt="x^4-3x^3-17x^2+39x-20?" align="absmiddle" class="latex-formula">
A. x-1
B. x+4
C. x-5
D. x+1

1 answer:

True [87]3 years ago

4 0

Answer:

D.

$x + 1$

Step-by-step explanation:

$x^4-3x^3-17x^2+39x-20 = \\ = (x - 5) {(x - 1)}^{2} (x + 4)$

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3 years ago

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2 years ago

Solve the system of equations -3x+7y=-18 and 4x-4y=8 by combining the equations.

Aleksandr-060686 [28]

Answer:

$\huge \colorbox{red}{(x,y)=(-1,-3)}$

Step-by-step explanation:

multiply first equation by 4 and second by 3 respectively:

$\begin{cases} \displaystyle - 12x + 28y = - 72 \\ \: \: \displaystyle \: 12x - 12y = 24 \end{cases}$

combine the equations:

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divide both sides by -48:

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simplify multiplication:

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cancel 12 from both sides:

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3 years ago

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(3x+1)(x-2)+ax+b=3x^2+8x-5<br> Work out the values of a and b

Musya8 [376]

Answer:

a = 13, b = - 3

Step-by-step explanation:

Expand the left side and compare like terms on both sides

(3x + 1)(x - 2) ← expand using FOIL

= 3x² - 5x - 2

left side = 3x² - 5x - 2 + ax + b ← combine like terms

= 3x² + x(a - 5) + b - 2

right side = 3x² + 8x - 5

For the 2 sides to be equal then

a - 5 = 8 ( add 5 to both sides )

a = 13

and

b - 2 = - 5 ( add 2 to both sides )

b = - 3

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2 years ago