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anzhelika [568]
3 years ago
8

43.586 rounded to the nearest tenth

Mathematics
2 answers:
Kaylis [27]3 years ago
7 0
When you round to the nearest tenth, it is just to the first number after the decimal and if the following number is 5 or greater you round the number up one, if it is 4 or less you leave the number the same. In this case 43.586 rounds to 43.6
Alenkinab [10]3 years ago
6 0
43.600 we leared this in school so the answer should be 43.600
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valina [46]

ANSWER

D.

9 {y}^{2}  - 4 {x}^{2}- 36y + 16x - 16 = 0

EXPLANATION

The standard equation of the hyperbola is

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We multiply through by 36 to obtain:

9 {(y - 2)}^{2}  - 4( {x - 2)}^{2}  = 36

We now expand to get,

9( {y}^{2}  - 4y + 4) - 4( {x}^{2}  - 4x + 4) = 36

Expand :

9 {y}^{2}  - 36y + 36  - 4 {x}^{2}  + 16x - 16 = 36

To get the general form, we equate everything to zero to get,

9 {y}^{2}  - 4 {x}^{2}- 36y + 16x - 16 = 0

The correct choice is D.

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Pani-rosa [81]

Answer:

  {1, (-1±√17)/2}

Step-by-step explanation:

There are formulas for the real and/or complex roots of a cubic, but they are so complicated that they are rarely used. Instead, various other strategies are employed. My favorite is the simplest--let a graphing calculator show you the zeros.

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It can also be informative to add the coefficients in both cases--as is, and with the odd-degree term signs changed. Here, the sum is zero in the first case, so we know immediately that x=1 is a zero of the expression. That is sufficient to help us reduce the problem to finding the zeros of the remaining quadratic factor.

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Using synthetic division (or polynomial long division) to factor out x-1 (after removing the common factor of 4), we find the remaining quadratic factor to be x²+x-4.

The zeros of this quadratic factor can be found using the quadratic formula:

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The given expression factors as ...

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