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irina [24]
3 years ago
10

a city us growing at the rate of 0.9% annually. if there were 3619000 residents in yhe city in 1994, find how many to the neares

t ten thousand are living in that city in 2000. use y=3619000(2.7)^0.009t
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0
For this case we have the following equation:
 y = 3619000 (2.7) ^ 0.009t
 We must evaluate the equation for the year 2000.
 Therefore, we must replace the following value of t:
 t = 2000 - 1994
 t = 6
 Substituting we have:
 y = 3619000 (2.7) ^ (0.009 * 6)
 y = 3818407.078
 Round to the nearest ten thousand:
 y = 3820000
 Answer:
 
3820000 residents are living in that city in 2000
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