Repeating decimal means that the numbers after the decimal point are repeating constantly such as 8.3333333.....and so on. Or a number that repeats a pattern forever.
So <span>15.24 </span>is <u>NOT</u> a repeating decimal because after the decimal point the number 24 is not repeating.
This would make the number a repeating decimal - 15.24242424242424242424...
Answer:
36
Step-by-step explanation:
64 minus 44 + 64 divide by 4
Answer:
I can't see the picture
Step-by-step explanation:
f(x) = 7 is a even function
<em><u>Solution:</u></em>
Given that we have to find the even function
A function is even if and only if f(–x) = f(x)
<em><u>Steps to follow:</u></em>
Replace x with -x and compare the result to f(x). If f(-x) = f(x), the function is even.
If f(-x) = - f(x), the function is odd.
If f(-x) ≠ f(x) and f(-x) ≠ -f(x), the function is neither even nor odd.
<h3>Option 1</h3>
![f(x) = (x - 1)^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%201%29%5E2)
Substitute x = -x in above function
![f(-x) = (-x - 1)^2](https://tex.z-dn.net/?f=f%28-x%29%20%3D%20%28-x%20-%201%29%5E2)
Thus ![f(-x) \neq f(x)](https://tex.z-dn.net/?f=f%28-x%29%20%5Cneq%20f%28x%29)
So this is not a even function
<h3>Option 2</h3>
f(x) = 8x
Substitute x = -x in above function
f(-x) = 8(-x) = -8x
Thus ![f(-x) \neq f(x)](https://tex.z-dn.net/?f=f%28-x%29%20%5Cneq%20f%28x%29)
So this is not a even function
<h3>Option 3</h3>
![f(x) = x^2 - x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E2%20-%20x)
Substitute x = -x in above function
![f(-x) = (-x)^2 - (-x) = x^2 + x](https://tex.z-dn.net/?f=f%28-x%29%20%3D%20%28-x%29%5E2%20-%20%28-x%29%20%3D%20x%5E2%20%2B%20x)
Thus ![f(-x) \neq f(x)](https://tex.z-dn.net/?f=f%28-x%29%20%5Cneq%20f%28x%29)
So this is not a even function
<h3>Option 4</h3>
f(x) = 7
f(-x) = 7
Thus f(-x) = f(x)
Thus it is a even function
The answer is B) all real numbers.
This is because no matter what value we plug in for x, it's absolute value will always be positive and therefore greater than -9.