Answer:
We want to craft:
a/b and c/d
where a, b, c and d can be 2, 3, 4 and 5.
Such that the distance in the number line between these two numbers is maximized.
Then we want one number to be really small, and the other to be really large.
Remember two things:
for numbers like a/b.
if a is smaller than b, then a/b is smaller than 1.
Now, if a is larger than b, then a/b is larger than 1.
And two things,
1/10 = 0.1
10/1 = 10
So when the numerator is larger, the distance displaced in the number line is larger.
Then we want to have:
a number where the numerator is the largest option and the denominator is the smallest option:
a/b = 5/2
And the two remaining options in such way that the numerator is smaller than the denominator:
c/d = 3/4.
The distance between these two numbers is:
D = 5/2 - 3/4 = 10/4 - 3/4 = 7/4.
<h2><u>

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Diameter = 4 cm
Radius = Diameter/2 = 2 cm
Area of circle :




Circumference of circle :



<h2>Therefore, </h2><h3>Diameter = 4 cm</h3><h3>Radius = 2 cm</h3><h3>Area = 12.56 cm²</h3><h3>Circumference = 12.56 cm</h3>
<h2><u>

</u></h2>
Circumference = 15 feet (given)
Radius :







Diameter = r×2 = 2.38 × 2 = 4.76 feet
Area :



<h2>Therefore, </h2><h3>Diameter = 4.76 feet</h3><h3>Radius = 2.38 feet</h3><h3>Area = 17.78 ft²</h3><h3>Circumference = 15 feet</h3>
<h2><u>

</u></h2>
Diameter = 2 cm (given)
Radius = D/2 = 2/2 = 1 cm
Circumference :



Area :



<h2>Therefore, </h2><h3>Diameter = 2 cm</h3><h3>Radius = 1 cm </h3><h3>Area = 3.14 ft²</h3><h3>Circumference = 6.28 feet</h3><h2 /><h2><u>

</u></h2>
Radius = 4.3 mm
Diameter = r×2 = 4.3 × 2 = 8.6 mm
Circumference :



Area :




<h2>Therefore, </h2><h3>Diameter = 8.6 mm</h3><h3>Radius = 4.3 mm</h3><h3>Area = 58.95 mm²</h3><h3>Circumference = 27 mm</h3>
6 the answerr is 6 hope that this helped
Answer:
Center of dilation → (0, 0)
Step-by-step explanation:
Vertices of a triangle ABC are A(3, 6), B(7, 6) and C(7, 3).
If this triangle is dilated by a scale factor of 'k' about the origin,
Rule for the dilation is,
(x, y) → (kx, ky)
If vertex A is dilated by a scale factor of 3 about the origin,
A(3, 6) → A'(3×3, 3×6)
→ A'(9, 18)
Therefore, center of dilation is origin (0, 0).