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2 years ago

Does anyone know please

Mathematics

2 answers:

Novay_Z [31]2 years ago

7 0

Answer:

8 hours and 54 minuter

Step-by-step explanation:

1 hour is equal to 60 minutes

we have 8 hours and 0.9 hours

0.9*60=54 minutes

we have 8 hours and 54 minuter

Nuetrik [128]2 years ago

6 0

Answer:

The last one

Step-by-step explanation:

First you need to figure out how many minutes are in 0.1 hours

you can do this by dividing 60 minutes by 10

you get 6

multiply 6 and 9 so that you can find out how many minutes 0.9 hours are

this leaves you with 54 minutes

so your answer is 8 hours and 54 minutes

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The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

katovenus [111]

Answer:

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

4) The data for shelter B are a symmetric data set.

True, the median is exactly 2 pounds away from each quartile which means it is symmetric.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

Step-by-step explanation:

We are given two box-plots, a box plot basically shows 5 statistical characteristics of a data set and they are

1. minimum value

2. Lower quartile

3. Median value

4. Upper quartile

5. Maximum value

Box-plot of dogs in shelter A:

The whiskers range from 8 to 30

Which means that the range is = 30 - 8 = 22

The box ranges from 17 to 28

Which means that the interquartile range is = 28 - 17 = 11

21 - 17 = 4

28 - 21 = 9

The median is not equal distance away from each quartile which means that the box-plot is not symmetric.

A line divides the box at 21

Which means that the median is = 21

Box-plot of dogs in shelter B:

The whiskers range from 10 to 28

Which means that the range is = 28 - 10 = 20

The box ranges from 16 to 20

Which means that the interquartile range is = 20 - 16 = 4

18 - 16 = 2

20 - 18 = 2

The median is exactly 2 pounds away from each quartile which means it is symmetric.

A line divides the box at 18

Which means that the median is = 18

Which is true of the data in the box plots?

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

2) The median weight for shelter B is greater than that for shelter A.

False

3) The data for shelter A are a symmetric data set.

False

4) The data for shelter B are a symmetric data set.

True

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

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3 years ago

Sofia is a helper for the kindergarten class and is in charge of picking a video for their end-of-year party. To choose which ty

Pavel [41]

Answer:

B,C

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained

Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of residents 65-years or older who had obtained a flu shot = $\frac{28}{111}$ = 0.25

n = sample of residents 65-years or older = 111

p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ , $0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ ]