Answer:
Im not entirely sure this is right but
0 = tan^-1(20 ÷ 25)
0 ≈ 38.65°
hope i helped lol
Answer:
of iv
+
2
(
4
−
)
=
2
+
6
−
3
x+2({\color{#c92786}{4-x}})=2x+6-3x
x+2(4−x)=2x+6−3x
+
2
(
−
+
4
)
=
2
+
6
−
3
Step-by-step explanation:
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Answer:
Step-by-step explanation:
complimentary angles, when added = 90 degrees
69 + 5n + 1 = 90
5n + 70 = 90
5n = 90 - 70
5n = 20
n = 20/5
n = 4 <====
Answer:
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
Step-by-step explanation:
Let
x ----> the original length pf the piece of metal
y ----> the original width pf the piece of metal
we know that
----> equation A
The volume of the box is equal to

we have



substitute in the formula of volume
----> equation B
substitute equation A in equation B

solve for y


Solve the quadratic equation by graphing
using a graphing tool
The solution is y=21
Find the value of x

therefore
The original dimensions of the piece of metal are
Length: 36 inches
Width: 21 inches
The answer is: [C]: " y = -2x - 1 " .
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