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3 years ago

12

The diagram shows the artificial lake when Amanda jogged twice around the lake she jogged a distance of 2,700 meters find the va

lue of x

1 answer:

STALIN [3.7K]3 years ago

6 0

2700 divided by 2 is 1350

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Could someone please take a look to see If I got my Math problem correct, Thank you.

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4 years ago

A $50 watch was marked up to $60. What is the markup rate? Is it an increase or decrease?

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3 0

3 years ago

Read 2 more answers

£1700 is invested for 3 years at 4% per year SIMPLE interest. Work<br>out the total interest

Crank

Answer:

$1912.27

Step-by-step explanation:

Simple interest rate formula: A = P(1 + r)^t

Simply plug in the known variables

A = 1700(1 + 0.04)³

A = 1700(1.04)³

A = 1700(1.12486)

A = 1912.27

5 0

3 years ago

ANSWER ASAP PLZ!!

Vikentia [17]

$\text{If is}\\\\\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2\end{array}$

Answer:

$\large\boxed{\left(-\dfrac{344}{69},\ -\dfrac{38}{3}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2-0.3y=4\\2.3x-y=1.2&\text{multiply both sides by (-0.3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}0.2-0.3y=4\\-0.69x+0.3y=-0.36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-0.69x+0.2=3.64\qquad\text{subtract 0.2 from both sides}\\.\qquad-0.69x=3.44\qquad\text{divide both sides by (-0.69)}\\.\qquad x=-\dfrac{3.44\cdot100}{0.69\cdot100}\\.\qquad \boxed{x=-\dfrac{344}{69}}\\\\\text{Calculate the value of y from first equation:}$

$0.2-0.3y=4\qquad\text{subtract 0.2 from both sides}\\-0.3y=3.8\qquad\text{divide both sides by (-0.3)}\\y=-\dfrac{3.8\cdot10}{0.3\cdot10}\\\boxed{y=-\dfrac{38}{3}}$

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$\text{If is}\\\\\left\{\begin{array}{ccc}0,2x-0,3y=4\\2.3x-y=1.2\end{array}\right$

Answer:

$\large\boxed{\left(-\dfrac{52}{7},\ -\dfrac{128}{7}\right)}$

Step-by-step explanation:

$\left\{\begin{array}{ccc}0.2x-0.3y=4&\text{multiply both sides by 10}\\2.3x-y=1.2&\text{multiply both sides by 10}\end{array}\right\\\\\left\{\begin{array}{ccc}2x-3y=40&\text{multiply both sides by (-10)}\\23x-10y=12&\text{multiply both sides by 3}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-20x+30y=-400\\69x-30y=36\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad49x=-364\qquad\text{divide both sides by 49}\\x=-\dfrac{364:7}{49:7}\\.\qquad\boxed{x=-\dfrac{52}{7}}$

$2\left(-\dfrac{52}{7}\right)-3y=40\\-\dfrac{104}{7}-3y=40\qquad\text{multiply both sides by 7}\\-104-21y=280\qquad\text{add 104 to both sides}\\-21y=384\qquad\text{divide both sides by (-21)}\\y=-\dfrac{384:3}{21:3}\\\boxed{y=-\dfrac{128}{7}}$

7 0

4 years ago

A small craft in lake Ontario sends out a distances signal. The coordinates of the boat in trouble are (57,64). One rescue boat

KatRina [158]

Answer:

The coast guard craft will get to the distressed boat the fastest.

Step-by-step explanation:

The coordinates of boat are (57,64).

The coordinates of rescue boat are (67,83).

The coordinates of coast guard craft are (65,46).

Both rescue crafts travel at the same rate. One of them will get to the distressed boat the faster, whose distance from the boat is least.

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance between boat and rescue boat is

$d_1=\sqrt{(67-57)^2+(83-64)^2}=21.4709105536\approx 21.47$

The distance between boat and coast guard craft is

$d_2=\sqrt{(65-57)^2+(46-64)^2}=19.6977156036\approx 19.70$

Since the distance between boat and coast guard craft is least, therefore coast guard craft will get to the distressed boat the fastest.

6 0

3 years ago