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3 years ago

What is the area of the sector?

Mathematics

1 answer:

xeze [42]3 years ago

8 0

Area of the sector is 981.3 cm²

Step-by-step explanation:

Step 1: Find the area of the sector where radius = 50 cm and central angle = 45°

Area of the sector = πr² (C/360), where r is radius and C is the central angle

⇒ Area = 3.14 × 50² × (45/360)

= 3.14 × 2500 × 1/8

= 7850/8 = 981.3 cm²

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Find the length of the unknown side round your answer to the nearest whole number

lions [1.4K]

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2 years ago

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Alika [10]

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3 years ago

Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0

drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

$2x+4y+z=0$

( - )

$(2x-2x)+(4y-4y)+(-4z-z)= (10-0)$

$-5z=10$

$z = - \frac{10}{5}$

z = -2

From the equation (5),

$x+3z=-7$

$x+(3)(-2)=-7$

$x = -7+6$

x = -1

From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

$2y - 4=2$

$2y=4-2$

$2y=2$

$y=\frac{2}{2}$

y = 1

Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

8 0

3 years ago

Solve for c. a(b − c)=d

Lilit [14]

A(b - c) = d
ab - ac = d
-ac = -ab + d
ac = ab - d
ac/a = (ab - d)/a
c = (ab - d)/a

Your answer will be A. c = (ab - d)/a. Hope this helps!

6 0

3 years ago

Read 2 more answers

10. Given that the total distance travelled is 4 km and that the initial aceleration is 4 m/s², find:a) the value of V.b) the va

andrezito [222]

The initial deceleration is 4 m/s^2, so this means that considering the first line segment, $\frac{V-100}{T}=-4 \implies V=100-4T$ .

The total distance traveled is 4 km, which is equal to 4000 meters. This is equal to the area under the graph, so $400T-\frac{1}{2}(100-V)(5T)=4000$ .

$400(100-4T)-\frac{1}{2}(4T)(5T)=4000\\\\40000-1600T-10T^2=4000\\\\10T^2 +1600T-36000=0\\\\T^2 +160T-3600=0\\\\(T+180)(T-20)=0\\\\T=20 (T > 0)\\\\\therefore V=100-4(20)=20$

6 0

1 year ago