You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
Answer:31 dived by 81 is 0.3703
Step-by-step explanation:
<em>Denote x2 by y.
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<em>(x2-3)7=(y-3)7
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<em>This is a binomial expansion in y, and you want the coefficient of y4 because y4=x8
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<em>You have 7 terms of (y-3) in (y-3)7. To get the fourth power of y, you need to choose y from four of the terms. The number of ways you can do this is the combinations of 7 things taken 4 at a time. This is:
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<em>7!/(4!3!)=35</em>
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<em>So, the coefficient of x8 in the given expansion will be 210.</em>
<em>HOPE IT HELPS</em>
<em>THANK YOU </em>
Answer:
It should have 20 vertices, and the name is dodecahedron
No because every x value has to have only one y value. In the relation, 2 has two y values: 1 and -3.
