Answer:
they are both 0 since they would not appear on a graph
Step-by-step explanation:
When you multiply by 100 you have to move the decimal place 2 places to the right.
When you multiply by 1,000 you have to move the decimal place 3 places to the right.
When you multiply by 102 and 103, there is no simple trick as with multiplying by 100 or 1,000.
Your final answer is B. <span>multiplying 31.04 by 1,000</span>
Answer:
- d, series and sequence diverge
- d, geometric/divergent
- c, e (geometric, |r|<1)
Step-by-step explanation:
<h3>1.</h3>
The sequence terms have a common difference of -5/8. That make it a non-trivial arithmetic sequence, so it diverges.
The series is the sum of terms of the sequence. Any non-trivial arithmetic series diverges.
(A "trivial" arithmetic series has a first term of 0 and a common difference of 0. It is the only kind of <em>arithmetic</em> series that doesn't diverge.)
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<h3>2.</h3>
The terms of the series have a common ratio of -2. That makes it a geometric series. The ratio magnitude is greater than 1, so the series diverges.
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<h3>3.</h3>
A sequence will converge only if the terms have a common difference of 0 or a common ratio with a magnitude less than 1. Of the offered choices, only C and E will converge:
c. geometric, r = 3/5
e. geometric, r = -1/6
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<em>Additional comment</em>
The convergence criteria stated for problem 3 applies only to arithmetic and geometric sequences. There are many other kinds of sequences that converge, but these are the kinds being considered in this problem set.
Since the perimeter of the square is 16cm, each side is 4cm.
If we subtract the area of the two unshaded triangles from the area of the square we will know the area of the shaded portion...
The small inverted triangle on the left has a height of 4 and a base of 1. The are of the bottom triangle has a height of 2 and a base of 4...
So the area of the two triangles is 4*1/2+2*4/2=2+4=6
The area of the square is just 4*4=16 so:
The shaded area is 16-6=10cm^2
The proportion of the shaded area to the total area is then:
10cm^2:16cm^2
5:8