Yoo ill give brainiest doe

schepotkina [342]

<span>1/4(x + 16) - x =

First, distribute the 1/4.

= 1/4x + 1/4 * 16 - x

= 1/4x + 4 - x

= 1/4x + 4 - 4/4x

= 1/4x - 4/4x + 4

= -3/4x + 4

$= -\dfrac{3}{4}x + 4$ </span>

8 0

3 years ago

The value of X in the figure ABCD witch is a rhombus

NeX [460]

Answer:

x = 10°

Step-by-step explanation:

The diagonals of a rhombus divide the figure into congruent right triangles. That means the two marked acute angles are complementary.

__

<h3>solve for x</h3>

Complementary angles total 90°, so the relation we can use to find x is ...

(3x -13) +(8x -7) = 90

11x = 110 . . . . . . . . . add 20

x = 10 . . . . . . . . . divide by the coefficient of x

The value of x is 10°.

5 0

2 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

Write a system of equations, with one equation describing the cost to bowl at Bowl-o-Rama and the other describing the cost to b

ZanzabumX [31]

Complete question :

Write a system of equations, with one equation describing the cost to bowl at Bowl-o-Rama and the other describing the cost to bowl at Bowling Pinz. For each equation, let x represent the number of games played and let y represent the total cost.

Bowl-O-Rama rents shoes for $2 and each game cost $2.50

Bowling Pinz rents shoes for $4 and each game cost $2

Answer:

Bowl-O-Rama:

y = $2 + $2.50x

Bowling pinz:

y = $4 + $2x

Step-by-step explanation:

The total cost is the sum of shoe rental plus the product of the unit game rate and the number of games played.

Total cost, y

x = number of games played

Bowl-O-Rama:

y = Shoe rent + (unit rate per game * number of games)

y = $2 + ($2.50 * x)

y = $2 + $2.50x

Bowling Pinz :

y = Shoe rent + (unit rate per game * number of games)

y = $4 + ($2 * x)

y = $4 + $2x

3 0

2 years ago

Yesterday tram charged $70 to babysit for 5 hours

slega [8]

Answer:

And?

Step-by-step explanation:

We need more context

3 0

3 years ago