Need help plz due on Monday I believe

Mathematics

2 answers:

ra1l [238]3 years ago

6 0

Answer:

1(a) = 10

1(b) = 9

1(c) = 12

2(a) = 8

2(b) = 10

2(c) = 1

Step-by-step explanation:

1(a) = 22 - 2.6

= 22 - 12 = 10

1(b) = 6 - 1/4 . 16 + 21 / 3

= 6 - 16/4 + 7

= 6 - 4 + 7

= 9

1(c) = (8-5). (5-3)^2

= 3*2^2

= 3*4

= 12

2(a) = 4(x-2)/(x-1) when x = 0

= 4(0-2)/ (0-1)

= 4*-2/-1

= -8 / -1

= 8

2(b) = (-3x^2 + 4) / 4 when x = -2

= (6^2 + 4) / 4

= (36 + 4) / 4

= 40 / 4 = 10

2(c) = [-2x/4 + 4*(x-1)] / x^2 - 1 when x = 2

= (-1 + 4 * 1) / 4 - 1

= 3 / 3

= 1

NemiM [27]3 years ago

5 0

1) a. 10
b. 9
c. 12

2) a. 4(x-2) / (x-1)
= 4(0-2) / (0-1)
= 4(-2) / (-1)
= -8/-1
= 8
b. -3x^2 + 4 / 4
= -3(-2)^2 + 4 / 4
= -3(4) + 4 / 4
= -12 + 4 / 4
= -8 / 4
= -2
c. [-2x/4 + 4 (x-1)] / x^2 - 1
= [-2(2)/4 + 4 (2-1)] / 2^2 - 1
= [-2(2)/4 + 4(1)] / 2^2 - 1
= [-2(2)/4 + 4(1)] / 4 - 1
= (-4/4 + 4)/ 4 - 1
= (-1 + 4) / 4 - 1
= 3 / 3
= 1

You might be interested in

Aiko is finding the sum (4 + 5i) + (–3 + 7i). She rewrites the sum as (–3 + 7)i + (4 + 5)i. Which statement explains the mathema

yan [13]

In this item, it can be seen that from an expression of,
(4 + 5i) + (-3 + 7i)
Aiko transformed the equation by factoring out the i's from the expression and wrote it as,
(4 + 5)i + (-3 + 7)i
Now this is wrong because i there is not a variable but a notation that 5 and 7 are imaginary numbers. In fact, she cannot factor out the i's because it is not present in both -3 and 4. The answer therefore to this item is the last sentence, "Aiko incorrectly used the distributive property by combining ..."

4 0

3 years ago

Read 2 more answers

If cos x = −6/7, and 90° < x < 180°, what is cos⁡(2x)?

Naddik [55]

Recall the double angle identity:

$\cos2x=\cos^2x-\sin^2x=2\cos^2x-1$