Need help plz due on Monday I believe
2 answers:
Answer:
1(a) = 10
1(b) = 9
1(c) = 12
2(a) = 8
2(b) = 10
2(c) = 1
Step-by-step explanation:
1(a) = 22 - 2.6
= 22 - 12 = 10
1(b) = 6 - 1/4 . 16 + 21 / 3
= 6 - 16/4 + 7
= 6 - 4 + 7
= 9
1(c) = (8-5). (5-3)^2
= 3*2^2
= 3*4
= 12
2(a) = 4(x-2)/(x-1) when x = 0
= 4(0-2)/ (0-1)
= 4*-2/-1
= -8 / -1
= 8
2(b) = (-3x^2 + 4) / 4 when x = -2
= (6^2 + 4) / 4
= (36 + 4) / 4
= 40 / 4 = 10
2(c) = [-2x/4 + 4*(x-1)] / x^2 - 1 when x = 2
= (-1 + 4 * 1) / 4 - 1
= 3 / 3
= 1
1) a. 10
b. 9
c. 12
2) a. 4(x-2) / (x-1)
= 4(0-2) / (0-1)
= 4(-2) / (-1)
= -8/-1
= 8
b. -3x^2 + 4 / 4
= -3(-2)^2 + 4 / 4
= -3(4) + 4 / 4
= -12 + 4 / 4
= -8 / 4
= -2
c. [-2x/4 + 4 (x-1)] / x^2 - 1
= [-2(2)/4 + 4 (2-1)] / 2^2 - 1
= [-2(2)/4 + 4(1)] / 2^2 - 1
= [-2(2)/4 + 4(1)] / 4 - 1
= (-4/4 + 4)/ 4 - 1
= (-1 + 4) / 4 - 1
= 3 / 3
= 1
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