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Mrrafil [7]
3 years ago
7

Please help!! Due really soon!

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

9514 1404 393

Answer:

  f(x) = 6x +1

Step-by-step explanation:

Differences in x-values (first row) are 1, 1, 1.

Differences in y-values (second row) are 6, 6, 6.

The constant ratio of differences (6/1) tells you the function is linear, and has a slope of m = 6/1 = 6.

Using the first point in the form ...

  y = mx + b

we have ...

  y = 6x + b

  7 = 6·1 + b . . . . (x, y) = (1, 7)

  1 = b . . . . . . subtract 6

Then the equation can be written ...

  y = 6x +1

In functional form, this is ...

  f(x) = 6x +1

You might be interested in
The displacement of a particle from a reference point at any instant is given by s = 3 t 2 - 4 t + 5 , where s is in metres and
lina2011 [118]

The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.

How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t

Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.

To learn more about this, tap on the link below:
brainly.com/question/2234298

#SPJ9

3 0
1 year ago
The area of a square is given by the expression s•s square inches, where s is the length of a side in inches. Write the expressi
grandymaker [24]

This can also be written as A = s^2 and the area would be 49 with a side length of 7.

In order to find this, you can stick 7 into the area equation.

A = s^2

A = 7^2

A = 49

6 0
4 years ago
Change the equation from standard form to slope-intercept form -5x-2y=-3
horrorfan [7]

Answer:Your Mom

<h2>Step-by-step explanation:Cause she is fat No but it srsly is 123</h2>
5 0
4 years ago
The law of cosine is A squared + B squared -2abcosC. find he value of 2abcosC 
Gnoma [55]
D I think but not 100% sure
8 0
4 years ago
Help me please please please i need it
goldenfox [79]

Answer:

Step-by-step explanation:

Remark

If you take one radius whose length is r and start it at (0,0) on one end and (r,0) at the other, and sweep it around so the (r,0) hits every point on the circumference of the circle, the radius will go through 360°.

You have only gone through 120°. That's no problem. All you have to do now is add a fraction that adjusts for the 120°.

Formula

Arc length = fraction * 2*pi * r

2*pi * r is the circumference

Arc Length = 2* (120/360) * pi * r

Givens

r = 13

pi = 3.14

Solution

Arc Length = (120/360) * 2 * pi * 13

Arc Length = 27.21

Answer

Arc Length = 27.21

7 0
2 years ago
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