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3 years ago

Please help!! Due really soon!

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

9514 1404 393

Answer:

f(x) = 6x +1

Step-by-step explanation:

Differences in x-values (first row) are 1, 1, 1.

Differences in y-values (second row) are 6, 6, 6.

The constant ratio of differences (6/1) tells you the function is linear, and has a slope of m = 6/1 = 6.

Using the first point in the form ...

y = mx + b

we have ...

y = 6x + b

7 = 6·1 + b . . . . (x, y) = (1, 7)

1 = b . . . . . . subtract 6

Then the equation can be written ...

y = 6x +1

In functional form, this is ...

f(x) = 6x +1

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In mathematics given that x=L2-L1/L1(O2-O1).

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1. L1 = $\frac{L2}{X(O2 -O1)}$

2. O2 = $\frac{L2 - L1(1 + XO1)}{XL1}$

Step-by-step explanation:

Given: x = $\frac{L2 - L1}{L1(O2 -O1)}$

1. To make L1 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

collect like terms,

L2 = xL1(O2 - O1) + L1

factorize the right hand side;

L2 = L1[x(O2 - O1)]

L1 = $\frac{L2}{X(O2 -O1)}$

2. To make O2 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

open the bracket to have;

L2 - L1 = xL1O2 - xL1O1

⇒ xL1O2 = L2 - L1 + xL1O1

O2 = $\frac{L2-L1 + XL1O1}{XL1}$

= $\frac{L2 - L1(1 + XO1)}{XL1}$

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