Answer
-26+4
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Answer:
-1.23 is the correct answer
Step-by-step explanation:
-0.3×4.1 = -1.23 because when multiplying the negative is given to the answer unless there are 2 negatives in which case they cancel out.
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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1)7; divide by 7 2)-3; divide by 2 3)8; divide by -4 4)54; multiply by 6 5)80; multiply by -10 6)-6; divide by -9 7)-5; divide by -12 8)-40; multiply by 20 9)-90; multiply by 10 10)20 11)615; plug in 205 for R and 3 in T. multiply by 3