Prove:
Using mathemetical induction:
P(n) = 
for n=1
P(n) = 
= 6
It is divisible by 2 and 3
Now, for n=k, 
P(k) = 
Assuming P(k) is divisible by 2 and 3:
Now, for n=k+1:
P(k+1) = 
P(k+1) = 
P(k+1) = 
Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also
divisible by 2 and 3.
Hence, by mathematical induction, P(n) = is divisible by 2 and 3 for all positive integer n.
Answer:
187
Step-by-step explanation:
a=12,d=17-12=5
nth term =a+(n-1)d
36th term=12+(36-1)5
=12+(35×5)
12+175
36th term=187
Answer:
45.44/71 - 1 = -0.36 = -36%
36% decrease.
Answer:
x= (-3 +- sqrt3)/2
Step-by-step explanation:
Answer:
16/15
Step-by-step explanation:
Simplify the following:
8/3 - 8/5
Put 8/3 - 8/5 over the common denominator 15. 8/3 - 8/5 = (5×8)/15 + (3 (-8))/15:
(5×8)/15 + (3 (-8))/15
5×8 = 40:
40/15 + (3 (-8))/15
3 (-8) = -24:
40/15 + (-24)/15
40/15 - 24/15 = (40 - 24)/15:
(40 - 24)/15
| 3 | 10
| 4 | 0
- | 2 | 4
| 1 | 6:
Answer: 16/15
