Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:

Compute the sample size as follows:

![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
<h3>
Answer: 300 square feet</h3>
Explanation:
The trapezoid has area of
A = h*(b1+b2)/2
A = 6*(10+18)/2
A = 84
The rectangle is 18 ft by 12 ft, which leads to an area of 18*12 = 216 sq ft.
Adding the two sub-areas gets us: 84+216 = 300
The total area of the house-shaped figure is 300 sq ft.
1 hour =$26, she has an hourly rate of 26 dollars
($40768/y)(y/52w)=$784/week
Seven hundred and eighty-four dollars per week.
Answer:
you don't you just try it numnut
Step-by-step explanation: