Answer:
first construct the base of 5.3 cm(bc)
make an angle of 60° in B [ use protactor or compass]
then construct the AB of 8 cm
now measure AD 5.3 cm
join D and C
Chris wants to triple 63.374. He says it must end in 9. Is he correct? Explain your answer.
1 answer:
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We need to cut it up and find the areas of each
ok so base=a^2
back sides are a^2 and a^2
total we have a^2+a^2+a^2=3a^2
we have now the 4 triangles, 2 of which are identical
the identical triangles are the side ones which are base a and height 1/2a
area of triangle=1/2bh
so the areas of them are 1/4a^2, times 2 since 2 of those triangles, 1/2a^2
add
3a^2+1/2a^2=7/4a^2
now the very top triangle and the cut corner triangle
very top is legnth a and base a so 1/2 a^2 is area
add
3 and 1/2a^2+1/2a^2=4a^2
we also need the small rectangles on side which is 1/2a times a times 2 since 2 of them=a^2 so a^2+4a^2=5a^2
now to find the corner bit in terms of a
use some imagination and lines to find legnths, right triangles and hypotonuse
the very top side is a√2 (45,45,90 angle/triangle)
we need to find slant height which is (a√6)/2
now
area=1/2bh
area=((a^2)√3)
add that
5a^2+(a^2)√3=250.5
find a
undistribute the a^2
(a^2)(5+√3)=501
use divide both sides by (5+√3)
a^2=501/(5+√3)
take squaer root of both sides
a= aprox 8.6267094364168 in
I hope this is right (should be, but alot done in head so maybe incorrect or off)
ok so base=a^2
back sides are a^2 and a^2
total we have a^2+a^2+a^2=3a^2
we have now the 4 triangles, 2 of which are identical
the identical triangles are the side ones which are base a and height 1/2a
area of triangle=1/2bh
so the areas of them are 1/4a^2, times 2 since 2 of those triangles, 1/2a^2
add
3a^2+1/2a^2=7/4a^2
now the very top triangle and the cut corner triangle
very top is legnth a and base a so 1/2 a^2 is area
add
3 and 1/2a^2+1/2a^2=4a^2
we also need the small rectangles on side which is 1/2a times a times 2 since 2 of them=a^2 so a^2+4a^2=5a^2
now to find the corner bit in terms of a
use some imagination and lines to find legnths, right triangles and hypotonuse
the very top side is a√2 (45,45,90 angle/triangle)
we need to find slant height which is (a√6)/2
now
area=1/2bh
area=((a^2)√3)
add that
5a^2+(a^2)√3=250.5
find a
undistribute the a^2
(a^2)(5+√3)=501
use divide both sides by (5+√3)
a^2=501/(5+√3)
take squaer root of both sides
a= aprox 8.6267094364168 in
I hope this is right (should be, but alot done in head so maybe incorrect or off)