4 years ago

Chris wants to triple 63.374. He says it must end in 9. Is he correct? Explain your answer.

Mathematics

1 answer:

alukav5142 [94]4 years ago

4 0

He is wrong. we are only looking at the last number which is 4
if we tripple 4 or 4*3 we get 12 which ends in 2, not 9

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Two students, X and Y, forgot to put their names on their exam papers. The professor knows that these two students do well on th

Luda [366]

Answer:

The probability that the good exam belongs to student X is 0.8571.

Step-by-step explanation:

It is provided that the probability that X did well in the exam is, P (X) = 0.90 and the probability that X did well in the exam is, P (Y) = 0.40,

Compute the probability that exactly one student does well in the exam as follows:

$P(Either\ X\ or\ Y\ did\ well)=P(X\cap Y^{c})+P(X^{c}\cap Y)\\=P(X)P(Y^{c})+P(X^{c})P(Y)\\=P(X)[1-P(Y)]+[1-P(X)]P(Y)\\=(0.80\times0.60)+(0.20\times0.40)\\=0.56$

Then the probability that X is the one who did well in the exam is:

$P(X\ did\ well\ in\ the\ exam)=\frac{P(X\cap Y^{c})}{P(X\cap Y^{c})+P(X^{c}\cap Y)}\\ =\frac{P(X)[1-P(Y)]}{P(X\cap Y^{c})+P(X^{c}\cap Y)} \\=\frac{0.80\times0.60}{0.56}\\=0.857143\\\approx0.8571$