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3 years ago

What are some fractions less than 1/2

Mathematics

2 answers:

bixtya [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Lemur [1.5K]3 years ago

3 0

1/3 and 1/4. and 1/5 and 2/6

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The sum of two consecutive odd integers is -124. Find two integers

SVETLANKA909090 [29]

$2n+1+2n+3=-124\\
4n+4=-124\\
4n=-128\\
n=-32\\\\
2n+1=-63\\
2n+3=-61$

5 0

3 years ago

How many square feet of outdoor carpet will we need for this hole

natita [175]

Answer: where are the number or picture ? not enough information to answer

3 0

3 years ago

Solve for x. 9x=5x 20 enter your answer in the box. x =

const2013 [10]

Collect the like terms
9x-5x=20
4x=20 divide both sided by 4
x=5

7 0

3 years ago

Read 2 more answers

A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th

baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.553, n = 10$

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003$

$P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039$

$P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219$

$P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724$

$P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552$

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0

3 years ago

Find the values of x and y that make these triangles congruent by the HL Theorem.

RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

2y = 3y - 2

2y - 3y = -2 Subtract 3y from each sides.

-y = -2

So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

x= 2+1

So, x=3 and y=2 make these triangles congruent.

So, the correct choice is 3. x = 3, y = 2.

7 0

2 years ago