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valentina_108 [34]
3 years ago
14

How do you solve 50 is 40% of what number

Mathematics
2 answers:
MArishka [77]3 years ago
7 0

50 is 40% of 125

You solve this by

X is the number that 50 is 40% of.

40/100 times x = 125

x = 50 times 100 divided by 40 = 125

40/100x125=50

Brainliest plz

vivado [14]3 years ago
3 0
40. 50
—- —- 50x100 divided by 40=125
100. x
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Tim and Tom are painters. Tim and Tom are painting a crate. Tom paints 10 sq ft per minute. They painted a particular crate in 1
slava [35]
Tom-------------- >10 sq ft per minute

Tim------------------- >3.5*10=35 sq ft per minute

 Both painters (10+35)=45 sq ft per minute

 let's assume a cubic unit crate----------> V1=1*1*1=1 feet3

<span>the total surface of the cube is S1=6*(1*1)=6 </span>sq ft

 if the volume of the cube increases twice 

V2=2 feet3 ------------------- >    2=x*x*x------------- >x=2^(1/3)

And the S2=6*(2^(1/3)*<span> 2</span>^(1/3)=9.5244 sq ft

V2/V1=9.5244/6=1.5874

Therefore

If Tim and Tom----------------------- > take 1 day----------- > to paint a crate V1

For the crate V2------------- > take 1.5874 days 

assuming an 8-hour work day

 0.5874*8=4.70 hr-------------- > 4 h 42 min

 The answer is 1 day 4h 42 min

6 0
3 years ago
The area of a triangle is 16 square units. The base of the triangle is x+4. The height of the triangle is x. Find x.
OLga [1]
The area of triangle formula is A = B*H  / 2
so it means 16 square = (<span>x+4) x /2
so x²+4x -32=0, D' = 2²- (-32)= 36, sqrt of D' = 6
so x = -2 -6 = -8 or x= -2 +6 = 4
x must be positive so x = 4</span>
5 0
3 years ago
Solve the polynomial equation. state the multiplicity of each root. 8x3 - 12x2 + 6x - 1 = 0
Alika [10]
Factorise to get (x - 0.5)^3 = 0
The equation has root 1/2 with multiplicity 3.
5 0
3 years ago
Let V denote the set of ordered triples (x, y, z) and define addition in V as in
icang [17]

Answer:

a) No

b) No

c) No

d) No

Step-by-step explanation:

Remember, a set V wit the operations addition and scalar product is a vector space if the following conditions are valid for all u, v, w∈V and for all scalars c and d:

1. u+v∈V

2. u+v=v+u

3. (u+v)+w=u+(v+w).

4. Exist 0∈V such that u+0=u

5. For each u∈V exist −u∈V such that u+(−u)=0.

6. if c is an escalar and u∈V, then cu∈V

7. c(u+v)=cu+cv

8. (c+d)u=cu+du

9. c(du)=(cd)u

10. 1u=u

let's check each of the properties for the respective operations:

Let u=(u_1,u_2,u_3), v=(v_1,v_2,v_3)

Observe that  

1. u+v∈V

2. u+v=v+u, because the adittion of reals is conmutative

3. (u+v)+w=u+(v+w). because the adittion of reals is associative

4. (u_1,u_2,u_3)+(0,0,0)=(u_1+0,u_2+0,u_3+0)=(u_1,u_2,u_3)

5. (u_1,u_2,u_3)+(-u_1,-u_2,-u_3)=(0,0,0)

then regardless of the escalar product, the first five properties are met for a), b), c) and d). Now let's verify that properties 6-10 are met.

a)

6. c(u_1,u_2,u_3)=(cu_1,u_2,cu_3)\in V

7.

c(u+v)=c(u_1+v_1,u_2+v_2,u_3+v_3)=(c(u_1+v_1),u_2+v_2,c(u_3+v_3))\\=(cu_1+cv_1,u_2+v_2,cu_3+cv_3)=c(u_1,u_2,u_3)+c(v_1,v_2,v_3)=cu+cv

8.

(c+d)u=(c+d)(u_1,u_2,u_3)=((c+d)u_1,u_2,(c+d)u_3)=\\=(cu_1+du_1,u_2,cu_3+du_3)\neq (cu_1+du_1,2u_2,cu_3+du_3)=cu+du

Since 8 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(ax,y,az)

b)  6. c(u_1,u_2,u_3)=(cu_1,0,cu_3)\in V

7.

c(u+v)=c(u_1+v_1,u_2+v_2,u_3+v_3)=(c(u_1+v_1),0,c(u_3+v_3))\\=(cu_1+cv_1,0,cu_3+cv_3)=c(u_1,u_2,u_3)+c(v_1,v_2,v_3)=cu+cv

8.

(c+d)u=(c+d)(u_1,u_2,u_3)=((c+d)u_1,0,(c+d)u_3)=\\=(cu_1+du_1,0,cu_3+du_3)=(cu_1,0,cu_3)+(du_1,0,du_3) =cu+du

9.

c(du)=c(d(u_,u_2,u_3))=c(du_1,0,du_3)=(cdu_1,0,cdu_3)=(cd)u

10

1u=1(u_1,u_2,u3)=(1u_1,0,1u_3)=(u_1,0,u_3)\neq(u_1,u_2,u_3)

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(ax,0,az)

c) Observe that 1u=1(u_1,u_2,u3)=(0,0,0)\neq(u_1,u_2,u_3)

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(0,0,0).

d)  Observe that 1u=1(u_1,u_2,u3)=(2*1u_1,2*1u_2,2*1u_3)=(2u_1,2u_2,2u_3)\neq(u_1,u_2,u_3)=u

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(2ax,2ay,2az).

8 0
3 years ago
How do you write 5.8 x 10 -4 in standard form
Misha Larkins [42]
Move the decimal point 4 times to the left
4 0
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