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3 years ago

Please help me I’m struggling

Mathematics

2 answers:

Scilla [17]3 years ago

7 0

Answer:

All

Step-by-step explanation:

We can check it by using the Pythagorean theorem.

$a {}^{2} + b {}^{2} = c {}^{2} = {3}^{2} + { \sqrt{27} }^{2} = 6 {}^{2} = 9 + 27 = 36 = 36 = 36$

${a}^{2} + {b}^{2} = c {}^{2} = {8}^{2} + {15}^{2} = {17}^{2} = 64 + 225 = 289 = 289 = 289$

$a {}^{2} + b {}^{2} = c {}^{2} = 5 {}^{2} + {5}^{2} = { \sqrt{50} }^{2} = 25 + 25 = 50 = 50 = 50 =$

Hope this helps ;) ❤❤❤

GREYUIT [131]3 years ago

4 0

Answer:

Step-by-step explanation:

the answer is c becuase i know this que

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Please help me if u give me an answer could u also give me an explanation on why that’s the answer.

Setler79 [48]

So it’s A

in all the other ones we can see that the angles in the same position as x and 75 are all equal

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3 years ago

Step by step<br> Please urgent

kotegsom [21]

Answer:

Below in bold.

Step-by-step explanation:

1) ( a^2 + b^2 = (a + b)^2 - 2ab

= 29 - 2(6)

= 29-12

= 17.

2). (x - y)^2 = x^2 + y^2 - 2xy

so 20 = 18 - 2xy

2xy = 18-20 = -2

xy = -1.

3). 1/x + x = 7

(1/ x + x)^2 = 1/x^2 + x^2 +x/x + x/x

= 1/x^2 + x^2 + 2

But(1/x + x)^2 = 7^2 = 49

so 1/x^2 + x^2 + 2 = 49

so 1/x^2 + x^2 = 49 - 2 = 47.

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3 years ago

Question#1 please. Thankyou

Angelina_Jolie [31]

The area of a rectangle is L x W, so 9(5+x) is the formula for the area in factored form. It can be simplified to 45+9x

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3 years ago

Please help me with the worksheet

aivan3 [116]

Answer:

9) a = ¾, <u>vertex</u>: (-4, 2), <u>Equation</u>: y = ¾|x + 4| + 2

10) a = ¼, <u>vertex</u>: (0, -3), <u>Equation</u>: y = ¼|x - 0| - 3

11) a = -4, <u>vertex</u>: (3, 1), <u>Equation</u>: y = -4|x - 3| + 1

12) a = 1, <u>vertex</u>: (-2, -2), <u>Equation</u>: y = |x + 2| - 2

Step-by-step explanation:

I could <u><em>only</em></u> work on questions 9, 10, 11, 12 in accordance with Brainly's rules. Nevertheless, the techniques demonstrated in this post applies to all of the given problems in your worksheet.

<h2><u>Definitions:</u></h2>

The given set of graphs are examples of absolute value functions. The <u>general form</u> of absolute value functions is: y = a|x – h| + k, where:

|a| = determines the vertical stretch or compression factor (wideness or narrowness of the graph).

(h, k) = vertex of the function

x = h represents the axis of symmetry.

<h2><u>Solutions:</u></h2><h3>Question 9) ⇒ Vertex: (-4, 2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (0, 5) and substitute into the general form (equation):

y = a|x – h| + k

5 = a| 0 - (-4)| + 2

5 = a| 0 + 4 | + 2

5 = a|4| + 2

5 = 4a + 2

Subtract 2 from both sides:

5 - 2 = 4a + 2 - 2

3 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{3}{4}\:=\:\frac{4a}{4}}$

a = ¾

Therefore, given the value of a = ¾, and the vertex, (-4, 2), then the equation of the absolute value function is:

<u>Equation</u>: y = ¾|x + 4| + 2

<h3>Question 10) ⇒ Vertex: (0, -3)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -2) and substitute into the general form (equation):

y = a|x – h| + k

-2 = a|4 - 0| -3

-2 = a|4| - 3

-2 = 4a - 3

Add 3 to both sides:

-2 + 3 = 4a - 3 + 3

1 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{1}{4}\:=\:\frac{4a}{4}}$

a = ¼

Therefore, given the value of a = ¼, and the vertex, (0, -3), then the equation of the absolute value function is:

<u>Equation</u>: y = ¼|x - 0| - 3

<h3>Question 11) ⇒ Vertex: (3, 1)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -3) and substitute into the general form (equation):

y = a|x – h| + k

-3 = a|4 - 3| + 1

-3 = a|1| + 1

-3 = a + 1

Subtract 1 from both sides to isolate <em>a</em>:

-3 - 1 = a + 1 - 1

a = -4

Therefore, given the value of a = -4, and the vertex, (3, 1), then the equation of the absolute value function is:

<u>Equation</u>: y = -4|x - 3| + 1

<h3>Question 12) ⇒ Vertex: (-2, -2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (-4, 0) and substitute into the general form (equation):

y = a|x – h| + k

0 = a|-4 - (-2)| - 2

0 = a|-4 + 2| - 2

0 = a|-2| - 2

0 = 2a - 2

Add 2 to both sides:

0 + 2 = 2a - 2 + 2

2 = 2a

Divide both sides by 2 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{2}{2}\:=\:\frac{2a}{2}}$

a = 1

Therefore, given the value of a = -1, and the vertex, (-2, -2), then the equation of the absolute value function is:

<u>Equation</u>: y = |x + 2| - 2

5 0

2 years ago

9.3% 1034 What is in scientific notation? 3.1 x 10"

Akimi4 [234]

Answer:

Please be more specific?

Step-by-step explanation:

I don't know what you are asking and the way you format the question is quite confusing.

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