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3 years ago

Find the slope and y-intercept of the graph of each equation. 5. y -- 2x - 7

Mathematics

1 answer:

OleMash [197]3 years ago

6 0

Answer:

If it is y=2x-7 the slope is

If it is y=-2x-7 the slope is

-2

The y-intercept is -7

Step-by-step explanation:

I don't really know how to give an explanation because the answers are in the equation so I'm sorry for that

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state wether the triangles could be proven congruent, if possible, by SSS or SAS. Then, write a congruency statement

ArbitrLikvidat [17]

What are the triangles

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3 years ago

Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade. Mrs. Benson has how many math assignmen

timofeeve [1]

Mrs. Benson has 184 math assignments left to grade.

<u>Step-by-step explanation:</u>

Here we have , Mrs. Benson has graded 46 math assignments but has 80% of the assignments left to grade.We need to find Mrs. Benson has how many math assignments left to grade. Let's find out:

Let total Number of math assignments be x , So According to question 46 math assignments are graded & 80% are left i.e.

⇒ $x = 46+\frac{80x}{100}$

⇒ $x -\frac{80x}{100}= 46$

⇒ $\frac{100x-80x}{100}= 46$

⇒ $\frac{20x}{100}= 46$

⇒ $\frac{x}{5}= 46$

⇒ $x=230$

Now , Assignments left to grade is :

⇒ $230-46$

⇒ $184$

Therefore , Mrs. Benson has 184 math assignments left to grade.

4 0

3 years ago

Which expression is equivalent to one over five m − 20?

Arada [10]

Answer:

1/5m - 20 = 1/5(m - 100)

Step-by-step explanation:

3 0

3 years ago

If I = “-1” then i2 =

jonny [76]

Answer:

-2

Step-by-step explanation:

negative times positive equal negative so

-1×2= -2

7 0

3 years ago

Read 2 more answers

A boat’s velocity, measured in meters per second, is described by vector b⇀=⟨3,4⟩. In two or more complete sentences explain how

Sedbober [7]

Answer: Velocity is a vector, so it has a magnitude and direction.

Speed is its magnitude, which is obtained from

|〈-3, 4〉 m/s| = √((-3 m/s)² + (4 m/s)²) = √(25 m²/s²) = 5 m/s

Its direction is an angle θ made with the positive horizontal axis, satisfying

tan(θ) = (4 m/s) / (-3 m/s) = -4/3 → θ = arctan(-4/3) + 180°n

where n is any integer. Now you have to consider that the x coordinate is negative and the y coordinate is positive, so 〈-3, 4〉 points into the second quadrant, and we get an angle there for n = 1 of about

θ ≈ 126.87°

Alternatively, you can use the vector 〈1, 0〉 in place of the axis, then compute the angle by relating it to the dot product, so θ is such that

〈-3, 4〉 • 〈1, 0〉 = |〈-3, 4〉| |〈1, 0〉| cos(θ)

(-3)•1 + 4•0 = √((-3)² + 4²) • √(1² + 0²) cos(θ)

-3/5 = cos(θ) → θ = arccos(-3/5) + 360°n

where again, n is any integer, and we get the same solution θ ≈ 126.87° in the second quadrant when n = 0.

Step-by-step explanation:

5 0

2 years ago