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8090 [49]
2 years ago
11

compare the graph of car A to the table of car B,C, & D to determine which car is traveling at the greatest speed.

Mathematics
2 answers:
Sidana [21]2 years ago
7 0
Car A is moving at 800/25 m/s which is 25m/s
B is moving 30/10 so 10m/s
C is moving at 60/4 so 15m/s
Car D is 90/6 so 15 tool.
Ans:Car A
notsponge [240]2 years ago
5 0
Car A trust me i did it and got the right answer
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Answer:

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Step-by-step explanation:

For an explanation of vocabulary questions, consult a dictionary or vocabulary list

1) angles ending in the same place are "co-terminal."

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2) The acute angle between the terminal ray and the x-axis is the "reference angle."

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3) Multiply radians by 180°/π to convert to degrees.

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  b) 7π/12 × 180°/π = (7/12)(180°) = 105°

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8 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:10 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:10 the acce
Daniel [21]

Answer: If we define 2:00pm as our 0 in time; then:

at t= 0. the velocity is 30 mi/h.

then at t = 10m (or 1/6 hours) the velocity is 50mi/h

Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:

a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/h^{2}

Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)

So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/h^{2}

5 0
2 years ago
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DedPeter [7]
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3 years ago
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irina1246 [14]
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