Answer:
1. (x + 2)² + (y - 9)² = 64
2. (x + 6)² + (y - 9/2)² = 100
3. (x - 15)² + (y + 10)² = 1
Step-by-step explanation:
Equation of a circle:
(x - h)² + (y - k)² = r²
1. Center: (-2, 9), Radius: 8
(x - (-2))² + (y - 9)² = 8²
(x + 2)² + (y - 9)² = 64
2. Center: (-6, 9/2), Radius: 10
(x - (-6))² + (y - (9/2))² = 10²
(x + 6)² + (y - 9/2)² = 100
3. Center: (15, -10), Radius: 1
(x - 15)² + (y - (-10))² = 1²
(x - 15)² + (y + 10)² = 1
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540 ft^2.
The area of the trapezoid = h/2 (10 + 18) = 14h.
By Pythagoras the height h = √(5^2 - 4^2) = 3.
So the area of the 2 trapezoidal bases = 2 * 14*3
= 84 ft^2.
Now we calculate the area of the four lateral rectangular sides:
= 10*12 + 18*12 + 2*5*12
= 456 ft^2.
Total area = 456 + 54
= 540 ft^2.
Answer: c=5.4
The two roots are 3/5 and 9/5
assume 5x2−12x c=0 is supposed to be 5x^2 - 12x + c = 0
p = (12 + sqrt(144-20c))/10
q = (12 - sqrt(144-20c))/10
p-3q=0,
1.2 + 0.1sqrt(144-20c) +
-3.6 + 0.3sqrt(144-20c) = 0
-2.4 + 0.4sqrt(144-20c) +2.4 = 2.4
sqrt(144-20c) = 2.4/0.4 = 6
144-20c=36
144-36=20c
c = 108/20 = 5.4
5x^2-12x+5.4=0
x = 3/5 or x = 9/5
