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masya89 [10]
3 years ago
6

Why is the dipole moment of so2 1.63 d but that of co2 is zero?

Chemistry
1 answer:
borishaifa [10]3 years ago
7 0
SO2<span> molecule </span>have a dipole moment<span> and a </span>CO2<span> molecule doesn't ... </span>Dipole moment<span> of </span>CO2<span> molecule </span>is zero<span>,becoz it is linear molecule,whereas </span>SO2<span> is angular</span>
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Determine the number of grams of carbon 3.14x 1023 atoms of carbon
tiny-mole [99]
<h3>Answer:</h3>

6.26 g C

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 3.14 × 10²³ atoms C

[Solve] grams C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 3.14 \cdot 10^{23} \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C})(\frac{12.01 \ g \ C}{1 \ mol \ C})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 6.26227 \ g \ C

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

6.26227 g C ≈ 6.26 g C

7 0
3 years ago
Read 2 more answers
Zinc is to be electroplated onto both sides of an iron sheet that is 20 cm2 as a galvanized sacrificial anode. It is desired to
Alexandra [31]

Answer:

The time required for the coating is 105 s

Explanation:

Zinc undergoes reduction reaction and absorbs two (2) electron ions.

The expression for the mass change at electrode (m_{ch}) is given as :

\frac{m_{ch}}{M} ZF = It

where;

M = molar mass

Z = ions charge at electrodes

F = Faraday's constant

I = current

A = area

t = time

also; (m_{ch}) = (Ad) \rho ; replacing that into above equation; we have:

\frac{(Ad) \rho}{M} ZF = It  ---- equation (1)

where;

A = area

d = thickness

\rho = density

From the above equation (1); The time required for coating can be calculated as;

[ \frac{20 cm^2 *0.0025 cm*7.13g/cm^3}{65.38g/mol}*2 \frac{moles\ of \ electrons}{mole \ of \ Zn} * 9.65*10^4 \frac{C}{mole \ of \ electrons }  ] = (20 A) t

t = \frac{2100}{20}

= 105 s

8 0
4 years ago
If fresh water flows into mono lake why is the lake salty
kaheart [24]
Mountains surround mono laks forming a closed hydrological basin--water fows into the lake, but it doesn't flow out. The only way for water to leave Mono Lake is through evaporation. ... Because the lake has no outlet, it is naturally saline.
3 0
3 years ago
In your own words how do plants on Earth affect the amount of carbon in Earth’s atmosphere?
Bumek [7]

Answer:

Plants take carbon dioxide out of the atmosphere, but they also have other effects, such as changing the amount of evaporation from the land surface. ... The plants absorb carbon dioxide for photosynthesis through the same pores (called stomata). But when carbon dioxide levels are high, the leaf pores shrink.

Explanation:

5 0
3 years ago
Read 2 more answers
A chemist needs 1.25 moles of sugar to dissolve in 1 liter of water how many grams of sugar needed
sdas [7]

Answer:

The mass of sugar used is 427.5 grams.

Explanation:

The formula of common sugar is \mathrm{C_{12}H_{22}O_{11}}.

Its molar mass of molecule is 342 grams per mole.

The number of moles of sugar used is equal to '1.25'

\mathbf{Mole=\frac{Mass \ given \ in \ grams}{Molar \ mass \ of \ molecule \ in \ grams}}

\textrm{Mass in grams}=\textrm{Mole} \times \textrm{Molar mass of molecule in grams}

\textrm{Mass in grams}= 1.25\times342

\mathbf{Mass \ in \ grams=427.5 g}

(NOTE : <em>You can calculate molar mass by adding the mass of all the atoms present in the atom. </em>

<em>Mass of Oxygen (O) = 16  ;  Total number of Oxygen atoms present = 11</em>

<em>Mass of Hydrogen (H) =1  ;  Total number of Hydrogen Atoms present = 22</em>

<em>Mass of Carbon (C) = 12   ;  Total number of Carbon atoms present = 12</em>

<em>Total mass of molecule = 12 × 12 + 1 × 22 + 16 × 11 = 342</em>)

4 0
3 years ago
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