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Dima020 [189]
3 years ago
11

How to do long multiplication

Mathematics
2 answers:
neonofarm [45]3 years ago
8 0
1. Write down the problem.
2. <span>Split up the smaller number into tens and ones.
3. </span><span>Multiply the larger number by the number in the tens digit. 
4. </span><span>Multiply the larger number by the number in the ones digit.
And then simply add up the two products. </span>
tino4ka555 [31]3 years ago
3 0
You just keep multiplying,preferably with a calculator
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A lumber company is making boards that are 2533.0 millimeters tall. If the boards are too long they must be trimmed, and if the
Slav-nsk [51]

Answer:

Step-by-step explanation:

n = sample size =14\\Mean = x bar = 2536.4 mm\\Var = s^2 = 64\\Std dev =s =8\\\\Population mean = 2533.0\\Mean difference = 2536.4-2533 = 3.4\\Std error of sample = 8/sqrt 14 =2.14\\Test statistic = (3.4)/2.14) = 1.59

Since sample size is small and population std dev is not known, t test should be used.

p value = 0.135849

Since p>0.05 we accept that samples have a mean equal to 2533mm

There is no sufficient evidence to support the claim that the boards are either too long or too short

7 0
4 years ago
Bisectors of angles A, B and C of a triangle ABC intersect its circumcircle at D, E and F respectively. Prove that the angles of
Simora [160]

Answer:

The region between a chord and either of its arcs is called a segment the circle.

Angles in the same segment of a circle are equal.

Step-by-step explanation:

Let bisectors of angles A, B and C of a triangle ABC intersect its circumcircle at D, E and F . 

Now from figure,

∠D = ∠EDF

∠D = ∠EDA + ∠ADF

Since ∠EDA and ∠EBA are the angles in the same segment of the circle.

So  ∠EDA  = ∠EBA

Hence  ∠D = ∠EBA + ∠FCA

Again  ∠ADF and ∠FCA are the angles in the same segment of the circle. 

hence ∠ADF = ∠FCA

Again since BE is the internal bisector of ∠B and CF is the internal bisector of ∠C

So ∠D = ∠B/2 + ∠C/2

Similarly

∠E = ∠C/2 + ∠A/2

and 

∠F = ∠A/2 + ∠B/2

Now ∠D = ∠B/2 + ∠C/2

=∠D = (180 - ∠A)/2

 (∠A + ∠B + ∠C = 180)

∠D = 90 - ∠A/2

∠E = (180 - ∠B)/2

∠E = 90 - ∠B/2

and ∠F = (180 - ∠C)/2

∠F = 90 - ∠C/2

8 0
3 years ago
PLEASE HELP
Roman55 [17]
A(n) = a(n-1)+9 means that we add 9 to the previous term to get the next term. Therefore the common difference is d = 9 this sequence is arithmetic.
The first term is a(1) = 21

Plug those two values into the arithmetic formula below and simplify
a(n) = a(1) + d * [ n - 1 ]
a(n) = 21 + 9 * [ n - 1 ]
a(n) = 21 + 9*n + 9*(-1)
a(n) = 21 + 9n - 9
a(n) = 9n+12

Answer is choice D
3 0
4 years ago
When you divide me by 5 the remainder is 4
xxMikexx [17]
20 ÷ 5 = 4 IDK how else to explain it, you just need a calculator
7 0
3 years ago
Read 2 more answers
Solve a-c. Please show all steps!
ziro4ka [17]

Answer:

The problem is stupidly written but the intercepts are:

(0 ,+/-625.02)

(+/-625.02, 0)

Radius is 625.02

Area 1,227,263.17 square miles

Step-by-step explanation:

7 0
3 years ago
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