Answer:


Step-by-step explanation:
Given


Solving (a): Reflect S across y-axis
The rule to reflect across y-axis is:

So, we have:

Hence:

Solving (b): Reflect Q across x and y-axis
The rule to reflect across x-axis is:

So:

The rule to reflect across y-axis is:

So:

Hence:

Answer:
y=1/3x+5 hope it helps you
Answer:
B
Step-by-step explanation:
Graph it, or just plug in and eliminate A C and D
I added a screenshot with the complete question along with its diagram.
Answer:vertical height is approximately 260 ft
Explanation:We can note that the sea level, vertical height and the distance traveled by the rocket all form a right angled triangle.
This means that the special trig functions can be applied.
These functions are as follows:
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse
tan θ = opposite / adjacent
From the given we have:
θ = 60°
opposite is the vertical height that we want to find
hypotenuse = 300 ft
Applying the sin function, we can get the vertical height as follows:
sin (60) = opposite / 300
opposite = 300 * sin (60)
opposite = 259.807 which is approximately 260 ft
Hope this helps :)
Answer:
Step-by-step explanation:
Let the required volume be x
<u>Use the ratio of gallon/volume to solve:</u>
- 1/0.13 = 20/x
- x = 20*0.13
- x = 2.6 ft³
With 20 gallons the scientist can cover 2.6 ft³ of water volume