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Svetach [21]
3 years ago
7

Consider the triangle. The measures of the angles of the triangle are 32°, 53°, 95°. Based on the side lengths, what are the mea

sures of each angle?
Mathematics
1 answer:
QveST [7]3 years ago
8 0
But you gave the measures of 3 angles of the triangle. Why did you have this question?
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I'm gonna go in order now, I'll mark you the brainiest and give you the more points
velikii [3]
Skew lines are lines that are not pararell or perpendicular.

The only lines that fit this explanation are AE and GF

Hope this helps!
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Read 2 more answers
4(x+3)=2(2x+9)
kramer

Answer:

m a t h w a y

Step-by-step explanation:

;)

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6. Meg measured the length of some pieces
alexandr1967 [171]

Answer:

longest length minus the shortest

Step-by-step explanation:

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Algebra 2- Common Functions PLEASE HELP!
RoseWind [281]

Answer: B

Step-by-step explanation:

Intersection of the 2 parts of the function is (0,0):

==> not A

the second part of the function is an half-line (and x =0)

Answer B

7 0
2 years ago
Darren wanted to see how contagious yawning can be. To better understand this, he conducted a social experiment in which he yawn
denis23 [38]

Answer:

10.5 minutes

Step-by-step explanation:

Thinking about the problem

The modeling function is of the form P(t)=A⋅Bf(t), where B=4B=4B, equals, 4 and f(t)=\dfrac{t}{10.5}f(t)=

10.5

t

​

f, left parenthesis, t, right parenthesis, equals, start fraction, t, divided by, 10, point, 5, end fraction.

Note that each time f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111, the quantity is multiplied by B=4B=4B, equals, 4.

Therefore, we need to find the ttt-interval over which f(t)f(t)f, left parenthesis, t, right parenthesis increases by 111.

Hint #22 / 3

Finding the appropriate unit interval

fff is a linear function whose slope is \dfrac{1}{10.5}

10.5

1

​

start fraction, 1, divided by, 10, point, 5, end fraction.

This means that whenever ttt increases by \Delta tΔtdelta, t, f(t)f(t)f, left parenthesis, t, right parenthesis increases by \dfrac{\Delta t}{10.5}

10.5

Δt

​

start fraction, delta, t, divided by, 10, point, 5, end fraction.

Therefore, for f(t)f(t)f, left parenthesis, t, right parenthesis to increase by 111, we need \Delta t=10.5Δt=10.5delta, t, equals, 10, point, 5. In other words, the ttt-interval we are looking for is 10.510.510, point, 5 minutes.

Hint #33 / 3

Summary

The number of people who yawned quadruples every 10.510.510, point, 5 minutes.

7 0
3 years ago
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