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3 years ago

7

Consider the triangle. The measures of the angles of the triangle are 32°, 53°, 95°. Based on the side lengths, what are the mea

sures of each angle?

1 answer:

QveST [7]3 years ago

8 0

But you gave the measures of 3 angles of the triangle. Why did you have this question?

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Chris found some colorful leaves under one tree. Under another tree, he

Lynna [10]

Answer:

x+y-3+6

or

x+y+3

5 0

3 years ago

CAN ANYBODY PLS HELP

Firdavs [7]

The correct options are

$5x = - 58 \:$ $5x + 4 = - 54$

<h3>How to find same value of x?</h3>

given that

$\frac{5}{6} x + \frac{2}{3} = - 9$

first find value of x to obtain the equations have the same value of x.

Find the L.C.M between the 6,3

$\frac{5x + 4}{6} = - 9$

Then Cross multiplication should be done

$5x + 4 = - 9 \times 6 \\ 5x + 4 = - 54 \\ 5x = - 54 - 4$

$5x = - 58$

Hence the correct options are

$5x = - 58$

$5x + 4 = - 54$

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1 year ago

Write a two-step equation that involves multiplication and subtraction, includes a negative coefficient, and had a solution of x

Contact [7]

9x - 21 = -42
This should be the type of equation that you're looking 4

7 0

3 years ago

Naomi plans to attend a four-year college that costs a total of $21,800 per year. Her family invests $9,500 in an account that e

Lyrx [107]

Answer:

yes

Step-by-step explanation:

i just did 450 times 12 times 5

450= money

12=months in year

5= how many years

4 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=4%20%20%20%7B%7D%5E%7Bx%20%7D%20%20%2B%206%20%7B%7D%5E%7Bx%7D%20%3D%209%20%7B%7D%5E%7Bx%7D%20%

Nookie1986 [14]

So, the value of x is 1.19

The question is an exponential equation

<h3>What is an exponential equation?</h3>

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

<h3>How to find x?</h3>

Since $4^{x} + 6^{x} = 9^{x}$ ,

Dividing through by 4ˣ, we have

$\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }$

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

$y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

$y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618$

Since y = (3/2)ˣ

Takung logarithm of both sides, we have

㏒y = ㏒(3/2)ˣ

㏒y = x㏒(3/2)

x = ㏒y/㏒(3/2)

x = ㏒y/㏒1.5

Since we do not have logarithm of a negative number, we use y = 1.618.

So, x = ㏒y/㏒1.5

x = ㏒1.618/㏒1.5

x = 0.2090/0.1761

x = 1.19

So, the value of x is 1.19

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11 months ago