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Gennadij [26K]
3 years ago
11

5x7/10=. The product lies between. And.

Mathematics
1 answer:
Ronch [10]3 years ago
6 0
5x7=35 35/10=3.5
so 3.5 is the answer

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1/2=8x+1 evaluate at the given value of x
cluponka [151]
You first subtract 1/2 and 1, which gets you -0.5.

then you are left with -0.5=8x

you divide 8 on both sides. which will now give you: x = -.0625

and -0.0625 is your answer :)
5 0
4 years ago
In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
REY [17]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

5 0
3 years ago
Read 2 more answers
ASAP WILL MARK BRAINLYEST <br><br><br>answer these two please!
Trava [24]

19.\\y=3x^2\\a=3,\ b=0,\ c=0\\\\\dfrac{-b}{2a}=\dfrac{-0}{2(3)=0\to x=0\\\\3x^2=0\ \ \ \ |:3\\\\x^2=0\to x=0

20.\\y=x^2-x-2\\a=1,\ b=-1,\ c=-2\\\\\dfrac{-b}{2a}=\dfrac{-(-1)}{2(1)}=\dfrac{1}{2}\to x=\dfrac{1}{2}\\\\x^2-x-2=0\\\\x^2-2x+x-2=0\\\\x(x-2)+1(x-2)=0\\\\(x-2)(x+1)=0\iff x-2=0\ \vee\ x+1=0\\\\x=2\ \vee\ x=-1

3 0
3 years ago
6m-2(7+3m)&gt;5(2m-3)-m
Tpy6a [65]

Answer:

Therefore the value is

m

Step-by-step explanation:

Given:

6m-2(7+3m)>5(2m-3)-m ....Given

Step 1. Applying Distributive Property A(B+C)=AB+AC we get

6m-2\times7-2\times 3m>5\times 2m-5\times 3-m

6m-14-6m>10m-15-m\\-14>9m-15

Step 2. Add 15 both the side

-14+15>9m-15+15\\1>9m

Step 3. Dividing both the side by 9

\dfrac{1}{9}>\dfrac{9m}{9}\\\\\dfrac{1}{9}>m

Therefore the value is

m

4 0
4 years ago
What is the domain of f(x) = 3^x
babunello [35]

Domain of 3ˣ = ( -∞, ∞ )

<em>Note : Domain of an exponential function is always ( -∞, ∞ )</em>

3 0
3 years ago
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