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Anestetic [448]
3 years ago
6

Une particule se déplace le long de la courbe y = 2x 2 – x + 3 et son abscisse est donnée par x = t 3 – 2t. Trouver la vitesse d

e la particule au temps t = 3.
Mathematics
1 answer:
Mars2501 [29]3 years ago
7 0
2*2=4 first you multiply  
4-1=3 then subtract  
3+3=6 now you add and that is your answer =6
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At what point on the curve y = 2 + 2ex − 4x is the tangent line parallel to the line 4x − y = 3? (x, y) =
Papessa [141]

Answer:

{ln 4, (2 + 2e^ln 4 − 4 ln 4)} or (1.39, 4.45)

Step-by-step explanation:

From this equation 4x − y = 3

-y = 3 - 4x

then, y = 4x - 3

From line equation y = mx + b

Therefore, the slope is 4

Since the are parallel line, they will have same slope

Finding the derivative of y = 2 + 2e^x − 4x

y = 2 + 2e^x − 4x

y' = 0 + 2e^x - 4

Therefore,

4 = 2e^x - 4

4 = e^x

x = ln 4 = 1.39

To find the y coordinate

y = 2 + 2e^x − 4x

y = 2 + 2e^ln 4 − 4 ln 4

y = 4.45

Hence, they are parallel at point (1.39 and 4.45)

3 0
3 years ago
on the playground 1/4 kids are on the jingle gym and 1/3pm are playing kick ball.how many kids are on the jungle gym or playing
DaniilM [7]
1/12 kids are playing on the playground
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3 years ago
mark invested 125 he earned a simple interest of 3% per year on the initial investment if no money was added or removed from the
postnew [5]

Answer:

$7.50

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formula for simple interest:

I = prt

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7 0
3 years ago
Read 2 more answers
Please help me answer the assignment in the picture.
Arturiano [62]

Mean: 52.2 because its the average of all the numbers

Range: 2   because (60-58)

Median: 53 because its in the middle of all the numbers

Mode : None

   

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