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hodyreva [135]
1 year ago
9

Do synethtic wig curls only come out if you put heat on it Answer Asap for brainlist

Mathematics
2 answers:
7nadin3 [17]1 year ago
8 0

Answer:

Yes, it is possible to curl a synthetic wig. But you should never attempt to use hot tools, like a curling iron, on a synthetic wig, unless the label specifically says that the wig can tolerate heat. If not, you can use foam rollers to curl the wig.

Natali5045456 [20]1 year ago
6 0

Answer:

. It will curl without heat. You Never attempt to use hot tools, like a curling iron, on a synthetic wig – unless the label specifically says that the wig can tolerate heat. If not, you can use foam rollers to curl the wig using the method below.

Step-by-step explanation:

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What is the solution to 6x^2 + 2x + 4 = 0?
Angelina_Jolie [31]

Step 1) Divide 6 and 4 (the last 2 numbers) and bring everything else down

<em>6x^24x+2x+4</em>

Step 2) Place in parentheses

<em>(6x^24x)+(2x+4)</em>

Step 3) Figure out what you can take out of each parentheses.

**In the first one, you can take out 6x because both numbers have x and 6 is the largest number 6 and 24 can go into.**

**In the second one, you can only take out 2 because 2 is the largest number that goes into 2 and 4.**

Step 4) You will know you did it correctly when the parentheses match up

<em>6x(x+4) + 2(x+4)</em> <<< this is how it should look

Answer: <em>(6x+2)(x+4)</em>

8 0
3 years ago
A certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of a writin
Morgarella [4.7K]

Answer:

(a) We reject our null hypothesis.

(b) We fail to reject our null hypothesis.

(c) We fail to reject our null hypothesis.

Step-by-step explanation:

We are given that a certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of a writing machine) is at least 10 hr.

A random sample of 18 pens is selected.

<u><em>Let </em></u>\mu<u><em> = true average writing lifetime under controlled conditions</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 hr   {means that the true average writing lifetime under controlled conditions is at least 10 hr}

Alternate Hypothesis, H_A : \mu < 10 hr    {means that the true average writing lifetime under controlled conditions is less than 10 hr}

<u>The test statistics that is used here is one-sample t test statistics;</u>

                           T.S. = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean

             s = sample standard deviation

             n = sample size of pens = 18

          n - 1 = degree of freedom = 18 -1 = 17

<u>Now, the decision rule based on the critical value of t is given by;</u>

  • If the value of test statistics is more than the critical value of t at 17 degree of freedom for left-tailed test, then <u>we will not reject our null hypothesis</u> as it will not fall in the rejection region.
  • If the value of test statistics is less than the critical value of t at 17 degree of freedom for left-tailed test, then <u>we will reject our null hypothesis</u> as it will fall in the rejection region.

(a) Here, test statistics, t = -2.4 and level of significance is 0.05.

<em>Now, at 0.05 significance level, the t table gives critical value of -1.74 at 17 degree of freedom.</em>

Here, clearly the value of test statistics is less than the critical value of t as -2.4 < -1.74, so we reject our null hypothesis.

(b) Here, test statistics, t = -1.83 and level of significance is 0.01.

<em>Now, at 0.051 significance level, the t table gives critical value of -2.567 at 17 degree of freedom.</em>

Here, clearly the value of test statistics is more than the critical value of t as -2.567 < -1.83, so we fail to reject our null hypothesis.

(c) Here, test statistics, t = 0.57 and level of significance is not given so we assume it to be 0.05.

<em>Now, at 0.05 significance level, the t table gives critical value of -1.74 at 17 degree of freedom.</em>

Here, clearly the value of test statistics is more than the critical value of t as  -1.74 < 0.57, so we fail to reject our null hypothesis.

8 0
3 years ago
NEED HELP ASAP
andreyandreev [35.5K]

Answer: 137.08 m tall

Step-by-step explanation:

100-77=23

596x0.23=137.08

5 0
2 years ago
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What is the volume of a cylinder with base radius 2 and height 9?
harkovskaia [24]

Answer:

113.04

Step-by-step explanation:

V of Cylinder = h x r^2 x 3.14 (or pi)

Therefore, V of Cylinder is 9 x 2^2 x 3.14 = 113.04

6 0
2 years ago
Simplify this please
aliina [53]

Answer:

2a +5

Step-by-step explanation:

7 0
2 years ago
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