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lozanna [386]
3 years ago
12

Given 0 below, if GH and JK are congruent, what is the measure of KOJ?

Mathematics
2 answers:
alexira [117]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Since GH and JK  are congruent then the central angles are congruent, that is

∠KOJ = ∠HOG = 68° → D

alexgriva [62]3 years ago
5 0

Answer:

it is 68

Step-by-step explanation:

I did the test and got 68

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Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,
Gelneren [198K]

I'll abbreviate the definite integral with the notation,

I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx

We're given

  • I(f,1,8)=9
  • I(g,1,8)=5
  • I(f,5,8)=4
  • I(g,1,5)=3

Recall that the definite integral is additive on the interval [a,b], meaning for some c\in[a,b] we have

I(f,a,b)=I(f,a,c)+I(f,c,b)

The definite integral is also linear in the sense that

I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)

for some constant scalars k,\ell.

Also, if a\ge b, then

I(f,a,b)=-I(f,b,a)

a. I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}

b. I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}

c. I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}

d. I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}

e. I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}

f. I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}

4 0
3 years ago
A company rents out 11 food booths and 24 game booths at the county fair. The fee for a food booth is $175 plus $5 per day. The
AURORKA [14]
11(175+5d) + 24(50+7d)
3 0
2 years ago
What is the volume of a cone with a base of 10 and height of 9
Leto [7]
The formula being used is V=\pi r^2(h/3)

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5 0
3 years ago
Helpp, since this question is a bit hard, ill give brainliest and 20 pts.
Morgarella [4.7K]

Step-by-step explanation:

A. When dealing with large numbers, sometimes it's easier to write them in a form of exponents of number ten. The value of the exponent shows how many times we multiply 10 by itself. That means that 10^3 is 10•10•10 or that 10^6 is 10•10•10•10•10•10.

So, when finding how many times on number is greater then the other, we need to divide them. We divide 8x10^6 by 2x10^5. It is done by dividing the numbers and subtracting the exponents; 8/2=4 and 10^6/10^5 is 10^6-5=10^1. So the correct answer is 4x10^1 which is 4x10, and that is 40.

B. Now, we have a total number of coins (2.25x10^5), and diametar of a coin (19mm = 19x10^-6km). Our task is to calculate the distance across which the coiks laid side-by-side would expand. We can find this by multiplying the number of coins with a diametar of single penny, 2.25x10^5•19x10^-6. Multiplying is done by multiplying the numbers (2.25x19=42.75) and adding the exponents (5+(-6)=5-6=-1). So, the distance is 42.75x10^-1km, which equals to 4.275 km. Obviously, this is less then the stated 5 km given in the text, so the reportet's statement is false.

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3 years ago
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