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4 years ago

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They have budgeted $3,000 for their reception, if the reception hall charges a $70 cleanup fee plus $35 per person, find the gre

atest number of people that they may invite and still stay with in their budget

1 answer:

saw5 [17]4 years ago

4 0

28,

70 + 35 = 105, then divide by 3,000 which equals 28.57142857143, but you want a full human so you round down to 28

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6 times a number is 27 less than the square of that number. Find the positive solution.

Sedaia [141]

Answer:

9

Step-by-step explanation:

6n = n² - 27

n² - 6n - 27 = 0

n² - 9n + 3n - 27 = 0

n(n - 9) + 3(n - 9) = 0

(n - 9)(n + 3) = 0

n = -3, 9

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3 years ago

Travis earned 92 bonus points. Zoe earned b more bonus points than Travis. Write an expression that shows how many bonus points

Serga [27]

92 + b= the amount of points Zoe earned

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4 years ago

Read 2 more answers

Find the length of l on the curve r(t)=5cos(3t)i-5sin(3t)j+3tk over the interval [3,7]

stealth61 [152]

$\mathbf r(t)=5\cos3t\,\mathbf i-5\sin3t\,\mathbf j+3t\,\mathbf k$
$\mathrm d\mathbf r(t)=\mathbf r'(t)\,\mathrm dt=(-15\sin3t\,\mathbf i-15\cos3t\,\mathbf j+3\,\mathbf k)\,\mathrm dt$

$\displaystyle\int_C\mathrm d\mathbf r(t)=\int_{t=3}^{t=7}\|\mathbf r'(t)\,\mathrm dt\|=\int_{t=3}^{t=7}\sqrt{225\sin^23t+225\cos^23t+9}\,\mathrm dt$
$=\displaystyle3\sqrt{26}\int_{t=3}^{t=7}\mathrm dt$
$=12\sqrt{26}$

4 0

4 years ago

A bookstore had 81 copies of a magazine. Yesterday the bookstore sold

olga2289 [7]

Answer:

The question is unclear, but if the book store sold 9 copies total, they sold 2 yesterday.

Step-by-step explanation:

I am not sure how many copies were sold in total but here is how you can solve it- Get the total amount of copies and subtract the number of copies sold in total. Then get the difference and subtract 7 from it. The difference is your answer.

7 0

3 years ago

N is a rational number.m is an irrational number.n2 cannot be an irrational number? why or why not

Korolek [52]

If n is rational, it means that

$n\in\mathbb{Q}\Rightarrow n=\frac{p}{q},\quad p\in\mathbb{Z},\quad q\in\mathbb{Z}^*$

Therefore when we do n² we can write it as

$n^2=\frac{p^2}{q^2},\quad p\in\mathbb{Z},\quad q\in\mathbb{Z}^*$

Remember that the product of two integer numbers is also an integer, therefore we can guarantee that

$p^2\in\mathbb{Z}\text{ and }q^2\in\mathbb{Z}^*$

Then we can confirm that n² is the quotient of two integers and the denominator is not zero, therefore, n² is always rational, it cannot be an irrational number

8 0

1 year ago