1) Area of trapezoid =1/2(base 1 +base 2)* height

$A= \frac{23 \frac{1}{3}+4 \frac{2}{3} }{2} *(12 \frac{3}{4} ) = \frac{27 \frac{3}{3} }{2} *( \frac{51}{4} ) = \frac{28}{2} * \frac{51}{4} = \frac{7*51}{2} = \frac{357}{2} =178 \frac{1}{2} x^{2}$

5 0

3 years ago

Let me know if anyone can answer this for me thank you.

Vladimir [108]

Let's calculate the slope of the A(3,1.5) and B(5, 2.5)

The formula of the slope m =(y₂-y₁)/(x₂-x₁)

m = (2.5 - 1.5)/(5 - 3)

m = (1)/(2) = 0.5
Aaron rate for mowing lawns is 0.5 Acre/Hour

8 0

2 years ago

Which statements are true regarding the rotational symmetry of the shape of a cross? Select three options.

Inga [223]

Answer:

The correct options are;

1) The shape maps unto itself after a rotation of 270 degrees

2) The smallest angle of rotational symmetry is 90 degrees

3) The shape maps unto itself after a rotation of 180 degrees

Step-by-step explanation:

We note that the shape of a cross which consists of two equal members (segments) bisecting each other at right angles such that when a member is placed vertically upright, the other member will be horizontal, therefore we have;

After rotation by 90 degrees, the vertical member will become horizontal and vice versa

After rotation by 180 degrees, the vertical member will become horizontal and vice versa again

Similarly, after rotation by 270 degrees, the once vertical member will become horizontal and the horizontal member will become vertical

6 0

2 years ago