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Varvara68 [4.7K]
4 years ago
10

suppose you choose a marble from a bag containing 3 red marbles, 3 white marbles, and 5 blue marbles. You return the first marbl

e to the bag and then choose again. Find P(red then blue)
Mathematics
1 answer:
Marta_Voda [28]4 years ago
8 0

Answer:

15/121 is the answer.

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Let p(x) = 7x + 5 and r(x) = x - 1. Find and evaluate (r x p) (5)
quester [9]

Answer: 39

Step-by-step explanation:

Given

P(x)=7x+5

r(x)=x-1

r(p(x))=7x+5-1=7x+4

so, r(p(5))

\Rightarrow r(p(5))=7\times 5+4=35+4=39

8 0
3 years ago
5x + 9 = 5 + 3x : solve
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5x - 9 = 5 - 3x

5x - 3x = 5 - 9

2x = -4

X = \frac{-4}{2} = -2

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

5 0
4 years ago
A number with the same value as 32
Olenka [21]
32*10=320 Hope you like and rate
3 0
3 years ago
Read 2 more answers
What is the equation of the line written in general form (2,4) (-1,-5)
elena-s [515]
First, you must find the slope, which is -5-4/-1-4, or 1.8, and then put it in point-slope form, or y-4=1.8(x-2), which simplifies to y-4=1.8x-3.6, and so put it in general/standard form, you have to subtract 1.8x from both sides and then add 4 to both sides, and lastly divide both sides of the equation by -1.8 to get x+y=1.889, or x+y=1.6/1.8.   This is not copied and pasted.
6 0
3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
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