Answer:
periodical databases
Explanation:
Among the various databases you can now access in a library, the periodical databases contains the text and other information about articles published in magazines, journal and newspapers.
This database allows you for example to easily search for all articles written about a specific event or person, and it will return you the list of articles you can then read from a single spot, no matter where or when the article was written.
The resource allocation section of the test plan contains the information regarding the features to be tested in the test plan.
<h3>What is resource allocation?</h3>
The distribution and disbursement of the total disposable resources within an organization towards the different functions and processes in an organization is referred to as resource allocation.
The main functionality of a resource allocation section in a test plan is to portray the features of the test that will be conducted by the team of experts.
Hence, the functions of resource allocation in a test plan are as aforementioned.
Learn more about resource allocation here:
brainly.com/question/17837067
#SPJ1
Answer:
Main Memory (RAM)
Explanation:
This is the memory which is directly accessible to the CPU. It can be called Main Memory, Prime Memory or simply 'Memory'
Answer:
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
Explanation:
The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).
Where f(x) is frequency of character x.
Lets consider the scenario when
f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005
Please see attachment for image showing the steps of construction of Huffman tree:- see attachment
From the Huffman tree created, we can see that endcoding e() of each character are as follows:-
e(a) = 0
e(b) = 10
e(c) = 110
e(d) = 1110
e(e) = 11110
e(f) = 11111
So we can see that maximum length of encoding is 5 in this case.