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Mazyrski [523]
2 years ago
15

Marissa bought 2 and 1/2 gallons of orange juice to make punch how many quarts of orange juice did Marissa Buy

Computers and Technology
2 answers:
Vladimir [108]2 years ago
5 0
1 gallon = 4 quarts
using this information, you can then use simple proportion.
if 1 gallon = 4 quarts 
then to find the amount of quarts in 2 and 1/2 gallons, you multiply 2 and 1/2 by 4 which should give you 10 gallons
Ksivusya [100]2 years ago
3 0
4 because 2 1/2 gallons equals 1 Gallon and 1 Gallon equals 4 quarts
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In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:

#include <stdio.h>

void swaparrayends(int arr[], int nrElements)
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int temp = arr[0];
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arr[nrElements - 1] = temp;
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void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);

for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
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getchar();
}

In higher languages like C# it becomes much simpler:

        static void Main(string[] args)
        {
            int[] myArray = {1, 2, 3, 4, 5};
            swaparrayends(myArray);
            foreach (var el in myArray)
            {
                Console.Write(el + " ");
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            Console.ReadLine();
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        static void swaparrayends(int[] arr)
        {
            int temp = arr[0];
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3 0
3 years ago
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Phantasy [73]

Answer:

U.S Department of Defense

Explanation:

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likoan [24]

\tt n1=int(input("Enter\: first\:no:"))

\tt n2=int(input("Enter\: second\:no:"))

\tt sum=n1+n2

\tt diff=n1-n2

\tt pdt=n1*n2

\tt div=n1//n2

\tt rem=n1\%n2

\tt print("Sum=",sum)

\tt print("Difference=",diff)

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