<u>Answer:</u>
- n = 1/9
<u>Step-by-step explanation:</u>
- 5/9 + n = 2/3
- => 5/9 + n = 6/9
- => n = 1/9
<u>Conclusion: </u>
Therefore, n = 1/9
Hoped this helped.
When Emily was born, she weighed 8.2 pounds. Two months later she weighed 10.15 pounds. How much weight did Emily gain in two mo
2 answers:
Hey there! Hello!
The easiest way to solve this problem is by subtracting one value from the other. In order to find how much weight Emily gained in two months, we need to find the difference between her initial weight and how much she weighed at the end of two months:
You can see that I added a zero onto the end of the 8.2. This just evens out the amount of numbers and makes the problem easier to visualize while keeping the amount the same.
From the result of the problem, Emily gained 1.95 pounds in two months.
I hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
The easiest way to solve this problem is by subtracting one value from the other. In order to find how much weight Emily gained in two months, we need to find the difference between her initial weight and how much she weighed at the end of two months:
You can see that I added a zero onto the end of the 8.2. This just evens out the amount of numbers and makes the problem easier to visualize while keeping the amount the same.
From the result of the problem, Emily gained 1.95 pounds in two months.
I hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
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Answer:
Th second condition is satisfied but the first one on this case it's not satisfied. So for this case it's not good apply the normal approximation to the distribution of p.
Step-by-step explanation:
We need to check the conditions in order to use the normal approximation.
Th second condition is satisfied but the first one on this case it's not satisfied. So for this case it's not good apply the normal approximation to the distribution of p.
If we have both conditions satisfied the general procedure is the following:
Data given and notation
n=23 represent the random sample taken
estimated proportion
is the value that we want to test
represent the significance level
Confidence=90% or 0.90
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.11.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
Calculate the statistic
On this case since the normal approximation it's not satisfid it's not correct calculate the statistic.
Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided . The next step would be calculate the p value for this test.
Since is a left tailed test the p value would be:
And if the we reject the null hypothesis. Otherwise w fail to the reject the null hypothesis.