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Ivenika [448]
3 years ago
14

Darren teaches a class of 25 students. He assigns homework 3 times a week, and each assignment consists of 12 problems. How many

problems must Darren correct each week?
Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
6 0
I'm guessing its 900 because 3 × 12 = 36
36 × 25 = 900
emmainna [20.7K]3 years ago
5 0

Answer:

Darren must correct 900 problems each week.

Step-by-step explanation:

Darren teaches a class of 25 students.

He assigns homework 3 times a week, and each assignment consists of 12 problems.

Darren gives homework for one student in a week = 12 × 3 =36 problems

Darren must correct problems each week = 36 × 25 = 900 problems

Darren must correct 900 problems each week.

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Answer:

Due to the higher Z-score, Demetria should be offered the job.

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Whichever applicant had grade with the highest z-score should be offered the job.

Demetria got a score of 85.1; this version has a mean of 61.1 and a standard deviation of 12.

For Demetria, we have X = 85.1, \mu = 61.1, \sigma = 12. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{85.1 - 61.1}{12}

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For Vincent, we have X = 299.2, \mu = 264, \sigma = 22.

Z = \frac{X - \mu}{\sigma}

Z = \frac{299.2 - 264}{22}

Z = 1.6

Tobias got a score of 7.26; this version has a mean of 7.1 and a standard deviation of 0.4.

For Tobias, we have X = 7.26, \mu = 7.1, \sigma = 0.4.

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.26 - 7.1}{0.4}

Z = 0.4

Due to the higher Z-score, Demetria should be offered the job.

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