Question

The height, h, in feet of a gold ball above the ground after being hit into the air is given by the equation. H=-16t2+64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground?

Answer 1

Answer:

4 seconds

Step-by-step explanation:

Given : $H = -16t^{2} +64t$

To Find: How many seconds does it take for the golf ball to hit the ground?

Solution :

Since we are given an equation : $H = -16t^{2} +64t$

Where H denotes height

t denotes the number of seconds elapsed since the ball was hit.

When he golf ball to hit the ground at that time the height becomes 0

So, put H = 0 in the equation

$H = - 16t^{2} +64t$

$0 = - 16t^{2} +64t$

$16t^{2} = 64t$

$16t = 64$

$t =\frac{64}{16}$

$t =4$

Thus it take 4 seconds for the golf ball to hit the ground