All categories

3 years ago

HA=2-bA , solve the equation for A

Mathematics

2 answers:

yaroslaw [1]3 years ago

7 0

HA + bA = 2
A(h+b) = 2
A = 2/h+b

sergiy2304 [10]3 years ago

4 0

Answer:

$A=\frac{2}{h+b}$

Step-by-step explanation:

$hA=2-bA\\\\hA+bA=2\\\\A(h+b)=2\\\\A=\frac{2}{h+b}$

You might be interested in

(-8,-2) and (-4,6)<br>what does y =

larisa86 [58]

Do you have an equation to go with that?

6 0

3 years ago

Answer both question carefully. All help needed on this. Thank you!

artcher [175]

Answer:

9) It will be congruent to the original image. Or stay the same.

10) It gets enlarged

Step-by-step explanation:

4 0

3 years ago

Lily spent 1/6 of her free time practicing soccer and 3 of her

melomori [17]

Answer:

She spent 4/6 of her free time.

Step-by-step explanation:

1/6 + 3/6 = 4/6

4 0

4 years ago

Consider the following differential equation. (A computer algebra system is recommended.) (1 + t2)y' + 4ty = (1 + t2)−2 (a) Draw

alina1380 [7]

Answer:

Step-by-step explanation:

a. Draw a direction field for the given differential equation

b. Based on the inspection of the direction field, describe ow solutions behave for large t.

The solution appear oscillatory

All solutions seems to converge to the function y0(t)=4

All solutions seems to converge to the function y0(t)=0

All solutions seems to seems to eventually have negative slopes a and hence decrease without bound

All solutions seems to seems to eventually have positive slopes a and hence increase without bound

As t-infinity

All solutions seems to seems to eventually have positive slopes a and hence decrease without bound

All solutions seems to converge to the function y0(t)=0

All solutions seems to seems to eventually have negative slopes a and hence decrease without bound

All solutions seems to converge to the function y0(t)=4

The solution are oscillatory

3 0

3 years ago

The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan

kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points $(x_1, y_1)$ and $(x_2,y_2)$ is,

d = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Length of PQ = $\sqrt{(1-1)^2+(2-6)^2}$

PQ = 4

Length of PR = $\sqrt{(1+4)^2+(2-2)^2}$

PR = 5

Length of QR = $\sqrt{(1+4)^2+(6-2)^2}$

QR = $\sqrt{25+16}$

= $\sqrt{41}$

= 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

= 4 + 6.4 + 5

= 15.4 yards

4 0

4 years ago