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Kazeer [188]
3 years ago
15

X-3y=-15 standard form to slope-intercept form

Mathematics
1 answer:
jeyben [28]3 years ago
7 0
The answer I got is y= 1/3x + 5
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Evaluate the algebraic<br> expression:<br> Plz answer quick
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Answer:

7,-5,-11

Step-by-step explanation:

-3(-4)-5=7

-3(0)-5=-5

-3(2)-5=-11

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3 years ago
In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded regi
Alexeev081 [22]
The area of a circle is <span>πr²
the outer circle area = </span><span>π 4x²
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</span>the outer circle area - <span>the inside circle area = </span><span>he shaded region
</span>π 4x² - 36π =<span>220π cm2 it implies x²-9 =55 and x²=64, and x =sqrt(64)=8
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4 years ago
I NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Dmitriy789 [7]

Answer:

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answer: 2

8 0
3 years ago
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Find the area of circle having its radius 15cm​
muminat

Answer:

A≈706.86

Step-by-step explanation:

welcome to brainly

4 0
3 years ago
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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0
2 years ago
Read 2 more answers
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