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Mrac [35]
2 years ago
7

Determine the value of x. Question 3 options: 1) 2.3 2) 10 3) 2.5 4) 2.11

Mathematics
1 answer:
krok68 [10]2 years ago
5 0

This question is incomplete, the diagram is missing. The complete diagram is uploaded along this answer.

Answer: (3) 2.5

Step-by-step explanation:

From the diagram, given that;

BF = 2.3, DF = x, FC = 5, FE = 4.6,

Now

by theorem

BF * FC = DF * FE

so we substitute

2.3 * 5 = x * 4.6

11.5 = 4.6x

x = 11.5 / 4.6

x = 2.5

therefore the value of x is 2.5

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Can someone show me how to do this?
Angelina_Jolie [31]
First, you know that 3/4 = .75. Now we can distribute. multipy -10*.75. Then multiply .75*2/5. Add those two answers together to get your final answer. 

4 0
2 years ago
Which of the following statements is true about the sequence? Select all that apply.
oksano4ka [1.4K]

Answer:

f(5)=33f of 5 is equal to 33

Step-by-step explanation:

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7 0
2 years ago
In a recent year, the ACT scores for the math portion of the test were normally distributed, with a mean of 21.1 and a standard
Natali5045456 [20]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

c) P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

d) We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(21.1,5.3)  

Where \mu=21.1 and \sigma=5.3

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

Part c

P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

Part d

We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

6 0
2 years ago
This scatter plot shows the relationship between students’ scores on the first exam in a class and their corresponding scores on
son4ous [18]

Answer:

D) 2 points

Step-by-step explanation:

Compare a couple of points in the clumps of points and that is your answer

7 0
2 years ago
The two lines graphed below are parallel. How many solutions are there to the system of equations?
coldgirl [10]

Solutions just means the amount of times the lines intersect, so there are no solutions. Since the lines are parallel, they’re going the exact same direction forever and ever, never intersecting. Hope this helps!

6 0
2 years ago
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