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LenaWriter [7]
3 years ago
7

Help please!!!

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0

Answer: the x coordinate of the solution is 1

Step-by-step explanation:

y = x^2 + 1 - - - - - - 1

y – 1 = x - - - - -2

From equation 2 , y = x + 1

Substituting y = x + 1 into equation 1, it becomes

x + 1 = x^2 + 1

x^2 + 1 - x - 1 = 0

x^2 - x - 1 + 1 = 0

x^2 - x = 0

Let x be on the right hand side of the equation and x^2 remains on the left hand side of the equation. It becomes

x^2 = x

Dividing the left hand side of the equation and the right hand side of the equation by x, it becomes

x^2/x = x/x

x = 1

Therefore, x = 1

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2/9 times n = -6. find the value of n. Please help!
Ne4ueva [31]

Answer: n = -27

Step-by-step explanation:

2/9n = -6

divide both sides by 2/9

n = -27

5 0
3 years ago
Read 2 more answers
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








7 0
3 years ago
F(x)=−7x^2 −x and g(x)=9x^2 −4x , find (f−g)(x) and (f−g)(1)
givi [52]

Answer:

f(x) = -7x² - x

g(x) = 9x² - 4x

To find ( f - g)(x) subtract g(x) from f(x)

That's

( f - g)(x) = - 7x² - x - ( 9x² - 4x)

= -7x² - x - 9x² + 4x

Group like terms

( f - g)(x) = - 7x² - 9x² - x + 4x

<h3>( f - g)(x) = - 16x² + 3x</h3>

To find (f - g)(1) substitute 1 into ( f - g)(x)

That's

(f - g)(1) = - 16(1) + 3(1)

= -16 + 3

<h3>= - 13</h3>

Hope this helps you

6 0
3 years ago
A woman invests a total of $20,000 in two accounts, one paying 2.5% and the other paying 8% simple interest per year. Her annual
djverab [1.8K]
Let's have a variable for each rate
x = account 1 (2.5% rate of interest)
y = account 2 (8% rate of interest) 

The formulas we need are: 
0.025x + 0.08y = 830 (amount of interest paid) 
x + y = 20 000 (combined amount invested) 

To solve we will use substitution (isolate for one variable and plugging into the other formula): 
x + y = 20 000
x = 20 000-y

0.025x + 0.08y = 830
0.025(20 000-y) + 0.08y = 830
500-0.025y+0.08y=830
500+0.055y=830
0.055y=330
y=6000

Now that we know y (the 2nd account) = $6000 we need to find x. We do this by using the previous formula.
x = 20 000-y
x=20 000 - 6000
x=14000

She invested $14 000 at a 2.5% interest rate and $6 000  at a 8% interest rate.

*Notes:
the percentages were converted into decimal form
you check your answer by plugging the numbers back into the 2 formulas we made

3 0
4 years ago
Factor the equation.​
goblinko [34]

Answer:

(5t+3), (t+3), (t-3)

Step-by-step explanation:

Reorder terms.

5t^3+3t^2-45t-27

Factor out the greatest common factor from each group

t^2(5t+3)-9(5t+3)

Factor the polynomial by factoring out the greatest common factor, 5t +3

(5t+3)(t^2-9)

Factor.

(5t+3), (t+3), (t-3)

hope this helps :)

3 0
3 years ago
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