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mel-nik [20]
2 years ago
7

How to divide -2 by 8

Mathematics
1 answer:
givi [52]2 years ago
4 0
The answer to your question is 2 divided by 8 or 8 divided by 2
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In each box, 20% of the total candies are grape flavored.
mrs_skeptik [129]

Answer:

9

Step-by-step explanation:

20 x 5 = 100

45/5 = 9

9 to 20 = 11

45 to 100 = 55

<u>55</u> = 5<--- Linear

11

(since the total answer is linear, the answer is right)

6 0
2 years ago
Read 2 more answers
Please help with this math problem
VashaNatasha [74]
-1 = (x-1)/3
(multiply both sides by 3)
-3 = x-1
(add 1 on both sides)
x=-2


7 0
3 years ago
Read 2 more answers
If the length of AO is double the length of CO, the length of BO is?
andreev551 [17]

BO is double that of DO. In other words, BO is two times longer than DO. The answer is choice B

For example, if DO were 3 units long, then BO would be 6 units long (2*3 = 6). This works because the triangles DCO and BAO are similar triangles. The corresponding sides are in the same ratio or proportion to one another. The larger triangle (BAO) has sides that are twice as long as the smaller triangle's (DCO) corresponding sides.

Side note: we can prove the triangles to be similar using the AA (angle angle) similarity theorem. The first pair of angles are the vertical angles DOC and BOA which are congruent to each other.The second pair is CDB and ABD which are congruent by the alternate interior angle theorem. Check out the attached image for a visual.

7 0
3 years ago
How do i make 5x+2y=4 into the form of y=mx+b
malfutka [58]

First you minus 2y on both sides and you get: 5x=-2y+4. Then you minus 4 on both sides to get 5x-4=-2y which in turn is y (-2y) = mx (5x) + b (-4) : -2y=5x-4

6 0
2 years ago
Make a flow chart showing that the triangles below are similar. NO LINKS OR CRAZY LANGUAGES.!!!!!!​
pantera1 [17]

Answer: See the attached image

You have the correct idea for the boxes you've filled out. For the first three boxes in column 1, I would be specific which segments you are dividing. So for instance, in the first box, it would be EG/EB = 55/11 = 5. Then the second box would be EF/EC = 35/7 = 5, and so on. The order of the boxes doesn't matter. The three boxes then combine together to help show that the triangles are similar. Specifically \triangle EFG \sim \triangle ECB. The order of the letters is important to help show how the angles pair up and how the sides pair up. We use the SSS similarity theorem here.

The second problem is the same idea, but we use one pair of congruent angles. So we'll use the SAS similarity theorem this time.

8 0
2 years ago
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