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hichkok12 [17]
2 years ago
7

Find the cube root of 1+¡^5​

Mathematics
1 answer:
Alla [95]2 years ago
7 0
  1. ¡^5= ¡
  2. so we have cuberoot of 1+¡
  3. x=1 y=1
  4. to find d modulus we have
  5. r=squaroot of 1²+ 1²= 2
  6. r= squaroot of 2
  7. we find the argard diagram by using
  8. tan(tha)=y/x
  9. tan(tha)=1/1
  10. tha=tan-¹ 1
  11. tha=45
  12. using the formula of root of complex number we have
  13. z=r^1/n (cos(tha+2k(180))/n +¡sin(tha+2k(180)/n) when k elemen z+ and n=3
  14. when k=0
  15. we have
  16. z=(squaroot of 2)^1/3 *1/2squaroot of 2
  17. like wise when k=1 and k=2
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