Find the cube root of 1+¡^5
1 answer:
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- ¡^5= ¡
- so we have cuberoot of 1+¡
- x=1 y=1
- to find d modulus we have
- r=squaroot of 1²+ 1²= 2
- r= squaroot of 2
- we find the argard diagram by using
- tan(tha)=y/x
- tan(tha)=1/1
- tha=tan-¹ 1
- tha=45
- using the formula of root of complex number we have
- z=r^1/n (cos(tha+2k(180))/n +¡sin(tha+2k(180)/n) when k elemen z+ and n=3
- when k=0
- we have
- z=(squaroot of 2)^1/3 *1/2squaroot of 2
- like wise when k=1 and k=2
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