Write a compound inequality that the graph could represent.

Mathematics

2 answers:

Otrada [13]4 years ago

8 0

<span> the answer is </span>-1 > x < 3.

Dmitry_Shevchenko [17]4 years ago

3 0

A solid dot on the graph of an inequality indicates that the number is contained within the inequality, so yo should use $\leq$ or $\geq$ to represent that situation, whereas a white dot indicates that the number is not contained within the inequality.

Our graph is telling us that $x$ is greater or equal than -1, and also $x$ is less than 3. So our inequality will be:

$-1 \leq x \leq 3$

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Rationalize the denominator of square root of negative 9 over open parentheses 4 minus 7 i close parentheses minus open parenthe

AlekseyPX

The answer is
$\frac{-6i-3}{5}$ .

Before we rationalize the denominator, we must simplify the numerator and denominator. We evaluate the square root on the top, and combine like terms on the bottom:
$\frac{\sqrt{-9}}{(4-7i)-(6-6i)}
\\
\\=\frac{\sqrt{9i^2}}{4-6-7i--6i}
\\
\\=\frac{3i}{-2-i}$

To rationalize the denominator, we multiply by the conjugate. The conjugate is found by making the imaginary term of the complex number, the i part, the opposite sign. The conjugate of -2-i is -2+i:

$\frac{3i}{-2-i}\times \frac{-2+i}{-2+i}
\\
\\=\frac{3i(-2+i)}{(-2-i)(-2+i)}
\\
\\=\frac{3i\times -2 + 3i\times i}{-2\times -2 + -2\times i + -2\times -i + -i\times i}
\\
\\=\frac{-6i+3i^2}{4-2i+2i-i^2}
\\
\\=\frac{-6i+3(-1)}{4-i^2}=\frac{-6i-3}{4-(-1)}=\frac{-6i-3}{5}$

7 0

3 years ago

Answer this for me, please.

Scilla [17]

Answer:

the answer would be .5 miles

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Omgggg help me for brainly what’s 4 x 5 divided by 2

yanalaym [24]