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Flura [38]
2 years ago
7

2}" alt="7x^{3} * 7x^{5}*7x^{2}" align="absmiddle" class="latex-formula"> ?
Mathematics
2 answers:
vaieri [72.5K]2 years ago
6 0

7x^3\cdot 7x^5\cdot 7x^2 =(7)^3\cdot x^{2+3+5} =343x^{ {10}}

Natasha_Volkova [10]2 years ago
4 0

{7x}^{3} . \:  {7x}^{5} . {7x}^{2} \\ 343 {x}^{3}   {x}^{5}  {x}^{2}  \\ 343 {x}^{10}  \\

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According to the Centers for Disease Control, about 18% of adolescents age 12-19 are obese. Suppose we take a random sample of 3
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Distinguish whether the ordered pair (16, -3) is a solution to:
sammy [17]
I believe you should try to plug in the ordered pair to see if the solutions work.

The ordered pair is (x,y) because x is on the x-axis and y is on the y-axis, therefore in (16,-3) the x=16 and y=-3.

Now substitute, meaning plug in those numbers into the equation.
For x+2y=10 would be 16+2(-3)=10
Now you just need to solve one side and see if it equals the other side.
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First you use order of operations to solve this. PEMDAS. So you multiply 2(-3) first because of the parenthesis and it being multiplication.
16+(-6) and when you have a positive number adding a negative number it’s going backwards of the number line, basically meaning subtraction in a way. Sorry if this confuses you, if you already know how to do negatives and such nevermind this part.
But 16+(-6)=10
So now you look at both side of the equation, does the left side equal to the right? 10=10, so yes. It is a solution for that equation.

Now for the next equation, 7y=-21
Again, plug in the ordered pair (16,-3) into the equation. Remember that it’s (x,y).
There is no x in this equation so no need to worry about that; you only plug in y for this one.
7(-3) Now you multiply. Whenever you multiply a positive number and a negative number, the answer will always be negative. So 7(-3) is -21.
Now look if the left side is equivalent to the right. Does -21=-21? Yes. The ordered pair is a solution.

(16,-3) is a solution to both equations.

Hope this helps!
5 0
3 years ago
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