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Flura [38]
2 years ago
7

2}" alt="7x^{3} * 7x^{5}*7x^{2}" align="absmiddle" class="latex-formula"> ?
Mathematics
2 answers:
vaieri [72.5K]2 years ago
6 0

7x^3\cdot 7x^5\cdot 7x^2 =(7)^3\cdot x^{2+3+5} =343x^{ {10}}

Natasha_Volkova [10]2 years ago
4 0

{7x}^{3} . \:  {7x}^{5} . {7x}^{2} \\ 343 {x}^{3}   {x}^{5}  {x}^{2}  \\ 343 {x}^{10}  \\

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Find the measure of the indicated angel
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Answer:

Answer is C

Step-by-step explanation:

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5 0
3 years ago
The expression 4x^3 +5x+10 divided by 2x + 3 is equivalent to
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Yes because to the number and it can be
4 0
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Factorise fully 9b-3b2
alexdok [17]

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3 0
3 years ago
The city of Raleigh has 9,200 registered voters. There are two candidates for city council in an upcoming election: Brown and Fe
sukhopar [10]

Answer:

A) The population of this survey is the registered voters in the city of Raleigh.

B) 9500

C) 200

D) 0.325

E) 3088

Step-by-step explanation:

A) The population of this survey is the registered voters in the city of Raleigh.

B) Population size can be defined as the total number of individuals in a population. Here the total number of individuals are the registered voters in the city. Therefore the size of the population is 9500.

c) Sample size is defined as the number of individual samples in a statistical test. Here the sample size is the 200 randomly selected registered voters. It is denoted as "n".

d) The sample statistic for the proportion of voters surveyed who said they'd vote for Brown would be:

p' = voters for brown / sample size

p' = \frac{65}{200} = 0.325

The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is 0.325

E) The expected number of voters for Brown based on the sample:

0.325 * 9500 = 3087.5

Approximately 3088

The expected number of voters for Brown based on the sample might be 3088 voters.

7 0
3 years ago
What is the answer for 4b -7 - 15b + 3
grandymaker [24]
If you combine like terms 4b and the 15b you will get 11b then -7 plus 3 you will get -4. The answer will just simply be -11b - 4
4 0
4 years ago
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